get part from text

[ashraf5000]

Hello, I am new to the php community
I have a problem with feedback code from api
I want to put a part in a variable
How is that ? please help
{"code": 0, "reason": "OK", "resp": "AT + CCFC = 1,3, \" 92061460 \ "\ r \ nOK \ r \ n"}
I want to put between \ r \ Variable \ r \
In this  case is == nOK
some time 
{"code":0, "reason":"OK", "resp":"AT+CCFC=1,3,\"  92061460\"\r\nERROR\r\n"}
in this case  = nERROR
need echo $varible 
i hope get your support

[gw1500se]

It is a bit hard to understand what you want but I think you are looking for str_replace.

[ashraf5000]

thanks for your replay

i need delete all text else  text between \ r \ xxxxxxxx \ r \ 

in this case  nOK

i need feed back  nOK   or  nERROR

i think we can use   explode   but i'am new in php and don't how do it 

[cyberRobot]

The following line looks like JSON. 

{"code":0, "reason":"OK", "resp":"AT+CCFC=1,3,\"  92061460\"\r\nERROR\r\n"}

You could try using PHP's json_decode() function to extract the code, reason, and resp variables. More information, including examples, can be found in the manual.
https://www.php.net/manual/en/function.json-decode.php

Then you could use explode() to break the "resp" component based off the double quote ("). Then chop off the third value, assuming the lines always look similar to the above.
 

 

Does the following line come from the API?

{"code": 0, "reason": "OK", "resp": "AT + CCFC = 1,3, \" 92061460 \ "\ r \ nOK \ r \ n"}

Unless I'm missing something, that's not valid code. Basically, the "resp" portion is equal to "AT + CCFC = 1,3, \" 92061460 \ "\ r \ nOK \ r \ n", which is surrounded by double quotes. In order to use double quotes in the middle of the string, they need to be escaped with a backslash. The first escaped quote is fine. The second one is not since there is a space between the backslash and the quote. The \r and \n entities are also invalid because of the extra spaces.