readfile() without executing HTML code

[phppup]

In a PHP file [php_one.php], I wrote some PHP code that contained a form.  I used ECHO to write the HTML inside of the PHP tags.

On another PHP page [php_two.php], I wanted to show the code that was used to create the first page [php_one.php].

My first effort provided an interesting result, since the PHP code was readable.  However, all HTML code was visible in its executed form.

There was an actual input field and a submit button (not the code used to produce them) in the context of my coding.

I have tried using:

file_get_contents("FILE")
$array = file("FILE")
readfile("FILE")

All results were similar and carried the same problem.

How can I view code so that even the HTML is visible as code?

[gw1500se]

One way is to translate all <> characters to &lt; and &gt; respectively. You may need to wrap it in <pre>...</pre> tags to format it.

[Barand]

Try

echo nl2br(htmlentities(file_get_contents('FILE')));

or

<div style='white-space: pre; font-family: monospace;'>
    <?=htmlentities(file_get_contents('FILE'))?>
</div>

 

Edited December 22, 2020 by Barand