Jump to content

how to define variables as numeric


ckir5951

Recommended Posts

Quote

Hi, I have some issues with my code. It's to refresh account payfile at end of month. Comments are noted
in code (//).
#1) how to define variables as numeric(I've tried several examples(forums and manuals)
#2) how to add several variables together so they are known as numeric(they are all decimal 8,2 in the database)
#3) Please, someone explain the "Undefined variable: mysql".

<?php
//Open a new connection to the MySQL server
$link = mysqli_connect("localhost", "root", "", "prerentdb"); 

// Check connection
if($link === false){ die("ERROR: Could not connect. " . mysqli_connect_error()); }
//MySqli Select Query
$sql = "select * FROM payfile";
echo "<center>";echo date('m/d/y');echo "<br />";
$due=0;
  $prevbal="prevbal";
  $latechg="latechg";
   $secdep="secdep";
   $damage="damage";
$courtcost="courtcost";
      $nsf="nsf";
   $amtdue="amtdue";
   $amtpaid="amtpaid";
  $paidsum="paidsum";

$due = $prevbal + $latechg + $secdep + $damage + $courtcost + $nsf; // Warning: A non-numeric value encountered x 5 line 21
$amtdue = $amtdue + $due;  Warning: // A non-numeric value encountered x 1 line 22

// if no payment or partial payment, add $10 to latechg field and amount not paid to prevbal field
if ($amtpaid < $amtdue)  // Notice: Undefined variable: amtpaid
	{ $latechg = $latechg + 10; $prevbal = $amtdue - $amtpaid;  }
// if payment = amtdue clear due
if ($amtpaid == $amtdue) // Notice: Undefined variable: amtpaid
	{ $prevbal = 0; $latechg = 0; }
// if over-payment subtract over-payment
// from prevbal field
if ($ampaid > $amtdue )  // Notice: Undefined variable: amtpaid
{ $amtdue = $amtpaid  - $amtdue;  $prevbal = 0; $latechg = 0;  }
$secdep = 0; $damage = 0; $courtcost = 0; $nsf = 0;

// refresh every record - give every record the below values
$amtpaid = '0.00';
$hudpay = '0.00';
$datepaid = ' ';
$paidsum = '0.00';
$comments = ' ';

// Perform a query, check for error
if (!$mysqli -> query("UPDATE payfile SET // Undefined variable: mysqli 
Fatal error: Uncaught Error: Call to a member function query() on null 
 prevbal='$prevbal',latechg='$latechg', hudpay='$hudpay', amtpaid='$amtpaid', 
datepaid='$datepaid', comment='$comment', paidsum='$paidsum' 
where unit = $unit"));
mysqli_query($sql) or die(mysql_error());
?>
Quote

these are error messages:

Warning: A non-numeric value encountered in C:\xampp\htdocs\property\refreshpayments.php on line 21

Warning: A non-numeric value encountered in C:\xampp\htdocs\property\refreshpayments.php on line 21

Warning: A non-numeric value encountered in C:\xampp\htdocs\property\refreshpayments.php on line 21

Warning: A non-numeric value encountered in C:\xampp\htdocs\property\refreshpayments.php on line 21

Warning: A non-numeric value encountered in C:\xampp\htdocs\property\refreshpayments.php on line 21

Warning: A non-numeric value encountered in C:\xampp\htdocs\property\refreshpayments.php on line 21

Warning: A non-numeric value encountered in C:\xampp\htdocs\property\refreshpayments.php on line 22

Notice: Undefined variable: ampaid in C:\xampp\htdocs\property\refreshpayments.php on line 32

Notice: Undefined variable: mysqli in C:\xampp\htdocs\property\refreshpayments.php on line 44

Fatal error: Uncaught Error: Call to a member function query() on null  on line 44

 

 

Link to comment
Share on other sites

$due = $prevbal + $latechg + $secdep + $damage + $courtcost + $nsf; // Warning: A non-numeric value encountered x 5 line 21

is equal to saying

$due = "prevbal" + "latechg" + "secdep" + "damage" + "courtcost" + "nsf";

these are not numeric.

 

Edited by dodgeitorelse3
Link to comment
Share on other sites

53 minutes ago, dodgeitorelse3 said:

$due = $prevbal + $latechg + $secdep + $damage + $courtcost + $nsf; // Warning: A non-numeric value encountered x 5 line 21

is equal to saying

$due = "prevbal" + "latechg" + "secdep" + "damage" + "courtcost" + "nsf";

these are not numeric.

As long as each one has the $ then it's a variable, and if undefined PHP will just treat it as null (and 0). The name-to-string thing applies only to constants, as in code like

const PREVBAL = 1;
const LATECHG = 2;
const SECDEP = 3;
const DAMGE = 4; // typo
const COURTCOST = 5;
const NSF = 6;

$due = PREVBAL + LATECHG + SECDEP + DAMAGE + COURTCOST + NSF;

and that behavior has actually been removed since PHP 8.

Link to comment
Share on other sites

sorry for how this sounds, but this code looks like a collection of pieces pasted together that have almost nothing to do with each other, there's missing and mismatched variables, and even an obsolete mysql_error() call in it. is this part of a programming class or self learning? what learning resources have you used to get to this point?

next, the most immediate problem, with the text strings being assigned to variables, resulting in the non numerical error messages when you try to add them together, appears like it was intended to be the result of fetching data from the SELECT query. this code isn't even executing that query, nor is it fetching the data from it. do you have a fundamental understanding of the steps needed to build, execute, and fetch data from a SELECT query? without this knowledge, it will be impossible for you to complete this assignment.

also, this SELECT query needs a WHERE clause in it to match the unit you are interested in, like the UPDATE query has. have you actually defined what your input data needs to be, what processing you are going to perform on that data, and what result you are trying to produce?

regardless of this being a class assignment or a real project, you should NOT update the values to keep track of amounts, since this does not provide an audit trail that would let you know if a programming mistake, accidental key press, or nefarious activity altered the values. you should instead insert a new row of data for every transaction that affects the amounts, just like your bank, credit card, utility, ... does this.

here are some suggestions that will modernize and simplify the code -

  1. use the much simpler PDO extension. someone has already posted a link to a tutorial on a different help forum where you have posted this.
  2. use exceptions for database statement errors and in most cases simply let php catch the exception. this will let you remove any existing database statement error handling logic since it will no longer get executed upon an error, simplifying the code.
  3. name the database connection variable as to the type of connection it holds, such as $mysqli or $pdo, then use this variable name throughout the code. this is the cause of the undefined $msyqli variable error. your code is putting the database connection into a variable named $link, not $mysqli. if you are not getting this fundamental requirement of using the same variable for a particular purpose through out the code, you are not going to be able to complete this assignment. 
  4. don't copy variables to other variables for nothing. just use the original variables that the data is in.

 

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.