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PHP Float and Number_Format


mcfc4heatons

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Good question.  Here's what I did:

$thenumber = 12;
echo "$thenumber with float: ".number_format((float)$thenumber, 2, '.', '').'<br>';
echo "$thenumber without float: ".number_format($thenumber, 2, '.', '').'<br>';
$thenumber = 5.2;
echo "$thenumber with float: ".number_format((float)$thenumber, 2, '.', '').'<br>';
echo "$thenumber without float: ".number_format($thenumber, 2, '.', '').'<br>';

Results:

12 with float: 12.00
12 without float: 12.00
5.2 with float: 5.20
5.2 without float: 5.20

Easy answer.  Doesn't seem to matter.

Edited by ginerjm
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(float) is casting $thenumber as a float.

But number_format() function definition (from the manual) is

number_format( float $num, int $decimals = 0, string|null $decimal_separator = ".", string|null $thousands_separator = ",") : string

therefore $thenumber is coerced to float type anyway. So, as demonstrated above, it makes no difference.

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