'each' function deprecated

[cornacum]

Hi everyone

Can someone help me to re-write in a loop that works in PHP 8.

I tried it myself but wasn't able to make it work.

This is the code:

            if ( is_array( $u ) ) {
                while( list( $key ) = each( $u ) ) {
                    $u = $u[$key];
                    break;
                }
            }

Thanks

[gw1500se]

Use foreach.

[Barand]

In this case, as it seems you want to replace the array with the value of the first element in the array, then

$u = current($u);

which would have been easier prior to v8 too.

[cornacum]

1 hour ago, gw1500se said:

Use foreach.

 

Can you actually help me and rewrite this in foreach loop? I can't figure out what I am doing wrong.

 

                while(list($uid, $userdata) = each($user)):
                    if ($userdata[2] == LEVEL_ADMIN)
                        $role = 'ADMIN';
                    elseif ($userdata[2] == LEVEL_USER)
                        $role = 'USER';
                    else
                        $role = 'Unknown';

 

[Barand]

Did you use gw1500se's link to foreach() in the manual?

There is no sign of in the code, so what did you try?

[ginerjm]

What does this array look like?  Is it an array of arrays or just an array of values?  Your two examples are confusing.

[cornacum]

1 hour ago, ginerjm said:

What does this array look like?  Is it an array of arrays or just an array of values?  Your two examples are confusing.

 

This is the loop within a function that populates the array at the bottom then returns it.  $users[$uid] at the end.

 

                while ( strlen($userdata) > 72 ) {
                    
                    $u = unpack( 'H144', substr( $userdata, 0, 72) );

                    //$uid = hexdec( substr($u[1], 0, 4) ).' ';
                    $u1 = hexdec( substr($u[1], 2, 2) );
                    $u2 = hexdec( substr($u[1], 4, 2) );
                    $uid = $u1+($u2*256);
                    $cardno = hexdec( substr($u[1], 78, 2).substr($u[1], 76, 2).substr($u[1], 74, 2).substr($u[1], 72, 2) ).' '; 
                    $role = hexdec( substr($u[1], 4, 4) ).' '; 
                    $password = hex2bin( substr( $u[1], 8, 16 ) ).' '; 
                    $name = hex2bin( substr( $u[1], 24, 74 ) ). ' '; 
                    $userid = hex2bin( substr( $u[1], 98, 72) ).' ';
                    
                    //Clean up some messy characters from the user name
                    $password = explode( chr(0), $password, 2 );
                    $password = $password[0];
                    $userid = explode( chr(0), $userid, 2);
                    $userid = $userid[0];
                    $name = explode(chr(0), $name, 3);
                    $name = utf8_encode($name[0]);
                    $cardno = str_pad($cardno,11,'0',STR_PAD_LEFT);
                    
                    if ( $name == "" )
                        $name = $uid;
                    
                    $users[$uid] = array($userid, $name, $cardno, $uid,intval( $role ), $password);
                    
                    $userdata = substr( $userdata, 72 );
                }

		 return $users;

 

And this is the loop fetching the array.

                while(list($uid, $userdata) = each($user)):
				
                    if ($userdata[2] == LEVEL_ADMIN)
                        $role = 'ADMIN';
                    elseif ($userdata[2] == LEVEL_USER)
                        $role = 'USER';
                    else
                        $role = 'Unknown';

 

Edited March 6 by cornacum

[ginerjm]

foreach ($users as $key->$data)
{
	list(($userid, $name, $cardno, $uid, $role, $password) = $data;
	if ($cardno == LEVEL_ADMIN)
		$role = 'ADMIN';
	elseif($cardno == 'LEVEL_USER')
		$role = 'USER';
	else
		$role = 'Unknown';
}

Not sure what is supposed to be the result since you are doing the same thing for every array element.  I suppose you might do an output as the last line of the loop such as:

echo "$key is $role<br>";

Edited March 6 by ginerjm
Used wrong var 'name'

[cornacum]

I will give that a try.

Thank you all for helping out.

 

 

[ginerjm]

oops I see that I type an extra left paren.  Please fix.