Immaterial Posted April 14, 2007 Share Posted April 14, 2007 This code is giving me an error: (Line 54) $info = mysql_query("SELECT * FROM war3 WHERE Replay# <= " . $first . " order by Replay# desc"); (Line 55) $data = mysql_fetch_array($info); $first is an integer variable. I have echoed it to test it, and in this particular case, it is "1". This is the error I am getting: "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in W:\www\Files\replays.php on line 55" The code is supposed to pull all entries from the table 'war3' that have Replay# of less than/equal to $first. I am unsure which version of MySQL I am using; it is the one that comes with the latest version of Uniform Server. Thank you for your assistance! Quote Link to comment Share on other sites More sharing options...
bubblegum.anarchy Posted April 14, 2007 Share Posted April 14, 2007 `#` is a comment character. Quote Link to comment Share on other sites More sharing options...
Immaterial Posted April 14, 2007 Author Share Posted April 14, 2007 Haha, wow, I feel sorta dumb... Thanks for the help, man. Quote Link to comment Share on other sites More sharing options...
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