Functions - Returning a variable.

[ataria]

Okay.

What I am looking to do is run a variable into a function ( function($variable); ) and then, have it at the end, predefine it in the function.

 

so, the script would look likeeee.

$variable = $row[variable];
function($variable);

and, then I can use it on the rest of the script as $variable.

 

is that possible, If so, how do i do it?

 

[ataria]

anyone?

[john010117]

First of all, please wait at least an hour before double posting. We all have lives, you know. Second of all, care to elaborate on your problem?

[ataria]

Okay.

I'll just make a quick little code snippet.

 

<?php
// would be the function.

function secure_int($variable){
$variable = intval($variable);
return $variable;
}

// would be the script.

secure_int($id);
echo "Your ID is ".$id."!";
?>

 

 

see how I didn't use "$id = function($id);"

 

is that possible? =/

[ataria]

.... anyone?

[lalabored]

Why don't you want to use $id = function($id)?

[ToonMariner]

<?php
// would be the function.

function secure_int($variable)
{
return intval($variable);
}

// would be the script.

$id = secure_int($id);
echo "Your ID is ".$id."!";
?>

 

the amazing thing here is that you ave managed to generate a function that does the exact same job as an already avialable built in function AND given it a longer name.

 

if you look at the code you could just do this and get exactly teh same result with a little time saving...

<?php
echo "Your ID is ". intval($id) ."!";
?>

 

or (if you use $id more in the script)

<?php
$id = intval($id);
echo "Your ID is ". $id ."!";
?>

[trq]

<?php

  function secure_int(&$variable){
    $variable = intval($variable);
  }

  secure_int($id);
  echo "Your ID is ".$id."!";
?>