miz_luvly@hotmail.com Posted March 24, 2006 Share Posted March 24, 2006 Hi all,Can someone help me solve this error plzzz :). my script seem to work fine but i am getting the following error.Fatal error: Call to undefined function: output() in C:\Program Files\Apache Group\Apache2\test\form1.php on line 60please refer to my code below, I am very advanced with php so plz excuse me if it a stupid mistake.thanks in advance :)<html><head><title></title></head><body><form name="myform" method="GET" action="form1.php"> <p> ID: <input type="text" size="5" name="keywords" id="post_code"/> </p><input type=submit></form></body><?phprequire 'conn.php';if (isset($_GET['keywords'])) { $sql = "select * from repactivity " . "where repactivity.post_code = '".$_GET['keywords']."'"; $result = mysql_query($sql); if (!$result) { echo 'Could not run query: ' . mysql_error(); } if ($result and !mysql_num_rows ($result)) { echo "<tr class='row1'><td>No results found that match the "; echo "search term(s) '<strong>" . $_GET['keywords'] . "</strong>'"; } else { while($row = mysql_fetch_array($result, MYSQL_BOTH)) { echo "<input type='text' name='full_name' value=".$row['full_name']."> <input type='text' name='report' value=".$row['report']."> <input type='text' name='outstanding' value=".$row['outstanding'].">"; { output_id($row['post_code'], TRUE); } }}?> Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted March 24, 2006 Share Posted March 24, 2006 Where is this function defined?[code]<?php output_id($row['post_code'], TRUE); ?>[/code]Ken Quote Link to comment Share on other sites More sharing options...
redbullmarky Posted March 24, 2006 Share Posted March 24, 2006 hi1, i can see an error with output() in your error message, but can only see a call to output_id in your script2, where is output_id or output defined? have you included the script with 'include' ?3, why is your php code at the bottom of your page, outside the html '<body>' tags?cheersMark Quote Link to comment Share on other sites More sharing options...
Honoré Posted March 24, 2006 Share Posted March 24, 2006 [!--quoteo(post=357958:date=Mar 24 2006, 06:50 PM:name=sab)--][div class=\'quotetop\']QUOTE(sab @ Mar 24 2006, 06:50 PM) [snapback]357958[/snapback][/div][div class=\'quotemain\'][!--quotec--]Hi all,Can someone help me solve this error plzzz :). my script seem to work fine but i am getting the following error.Fatal error: Call to undefined function: output() in C:\Program Files\Apache Group\Apache2\test\form1.php on line 60[/quote]Maybe you get this error message:Fatal error: Call to undefined function: output_id() in C:\Program Files\Apache Group\Apache2\test\form1.php on line 60and not:Fatal error: Call to undefined function: output() in C:\Program Files\Apache Group\Apache2\test\form1.php on line 60The reason is that you have a call to function output_id() but you have not written a function named output_id(). Quote Link to comment Share on other sites More sharing options...
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