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i need an if statement


skeg0

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im wondering if anyone can help me as im new to php.

I have a database driven php webpage that contains a menu at the top of each page called "top_template.php".. when a link is clicked to load a new page, it automatically reloads this "top_template" with a --- require "top_template.php"; --- command in the main body part of the page. however, there will be some times when i need to load up a different menu at the top depending on what the previous page was. so i was wondering if php has commands in it that will allow for an IF statement along the following lines:

if the referer (the page link that referred to this new page) == "menu1.php" THEN
require "menu2.php" ELSE require "menu1.php"

or

if menu2 is visible THEN require "menu2" ELSE
require menu1

it is just the direct syntax of these statements i need as it is written above, if anyone could help me i would be extremely grateful!!
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[!--quoteo--][div class=\'quotetop\']QUOTE[/div][div class=\'quotemain\'][!--quotec--]if the referer (the page link that referred to this new page) == "menu1.php" THEN
require "menu2.php" ELSE require "menu1.php"

or

if menu2 is visible THEN require "menu2" ELSE
require menu1[/quote]



[code]if ($referer == 'menu1.php')
       $req_menu = 'menu2.php';
else
       $req_menu = 'menu1.php';

//OR

$req_menu = ($referer == 'menu1.php') ? 'menu2.php' : 'menu1.php';[/code]
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[!--quoteo(post=358851:date=Mar 27 2006, 01:14 PM:name=Barand)--][div class=\'quotetop\']QUOTE(Barand @ Mar 27 2006, 01:14 PM) [snapback]358851[/snapback][/div][div class=\'quotemain\'][!--quotec--]
[code]if ($referer == 'menu1.php')
       $req_menu = 'menu2.php';
else
       $req_menu = 'menu1.php';

//OR

$req_menu = ($referer == 'menu1.php') ? 'menu2.php' : 'menu1.php';[/code]
[/quote]


thanks very much.. do i have to define these variables somewhere? the $referer and $req_menu or are they already known by php?
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