AV1611 Posted March 30, 2006 Share Posted March 30, 2006 Select avg(distinct (firstpass4.pass/(firstpass3.pass+firstpass4.pass))*100) as avg90 from firstpass3,firstpass4 where firstpass3.it_date=firstpass4.it_date order by firstpass3.it_date DESC limit 90 Link to comment https://forums.phpfreaks.com/topic/6186-solved-how-do-you-do-this/ Share on other sites More sharing options...
ober Posted March 30, 2006 Share Posted March 30, 2006 Did you run it? Did it provide any errors? Give us a little more information!!!!!!! We're not mind readers! Link to comment https://forums.phpfreaks.com/topic/6186-solved-how-do-you-do-this/#findComment-22334 Share on other sites More sharing options...
AV1611 Posted March 30, 2006 Author Share Posted March 30, 2006 I'm sorry, mysql error... I think you can't avg on as distinct... but I'm not sure... it doesn't work in my query browser either...// problem solved... if anyone wants to know... I'll post if you want it... but I doubt anyone cares... Link to comment https://forums.phpfreaks.com/topic/6186-solved-how-do-you-do-this/#findComment-22347 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.