Jump to content

resolving a fraction


earl_dc10
 Share

Recommended Posts

hey, I have a field where the user inputs a number, and it can be a fraction, I could have 2 fields where it's like <field> / <field> but I don't want to do that. I need to seperate the fraction ie (2/3 = 2, and 3) and I devised a way to do that :
[code]
for($x = 1; $x <= 100; $x++)
    {$temp = $input*$x;
    if(($temp/$x) == $input)
        {$num1 = $temp;
        $num2 = $x;
        break;
        }
    }
[/code]

it only reads the first half of the fraction, if I were to multiply $input by $x, it does this:
input will be 2/3 and $x will be 3, you'd think the output would be 2, right? it comes out as 6, it ignores what is after the "/" is there any way to resolve the fraction? ie, 2/3 = .6666... and go from there? thanks!

-J
Link to comment
Share on other sites

alright, this was an interesting question, so i did a little testing. first off, you can do this two ways. first, you can extract the numerator and denominator separately and THEN run the fraction:

[code]$components = explode('/', $_POST['fraction']);
if (count($components) > 1)
{
  it's an array with $components[0] as numerator, $components[1] as denominator
}
else
{
  it's just a number
}[/code]

a warning about using this method: it isn't exceptionally good at error-checking. if the user puts in more than one slash, it will only use the first and second numbers if you use $components[0] and $components[1].

otherwise, you can use the eval() function to process the $_POST['fraction'] as though it were an actual statement:

[code]eval("\$decimal = {$_POST['fraction']};");[/code]

if $_POST['fraction'] was "2/3" for example, what eval() would run is:

[code]$decimal = 2/3;[/code]

which is what you're after. this also takes care of the case that the number is not a fraction, since $decimal will just be assigned to the number.

hope this helps.
Link to comment
Share on other sites

thanks, that was exactly what I needed, also my "fraction finder" script shown above was extremely flawed notice
[code]
{$temp = $input*$x;
    if(($temp/$x) == $input)
// that was just stupid
[/code]
so I needed all the help I could get, thanks again!
Link to comment
Share on other sites

This thread is more than a year old. Are you sure you have something important to add to it?

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

 Share

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.