*SOLVED* mysql insert value as variable array
Posted 05 May 2006 - 02:06 PM
Posted 06 May 2006 - 05:24 AM
Posted 06 May 2006 - 11:00 AM
Please, take the time and do some research and find out how much it would have cost you to get your help from a decent paid-for source. A "roll-of-the-dice" freelancer will charge you $5-$15/hr. A decent entry level freelancer will charge you around $15-30/hr. A professional will charge you anywhere from $50-$100/hr. An agency will charge anywhere from $100-$250/hr. Think about all this when soliciting for help here. Think about how much money you are making from the work you are asking for help on. No, we do not expect you to pay for the help given here, but donating a few bucks is a fraction of the cost of what you would have paid, shows your appreciation, helps motivate people to keep offering help without the pricetag, and helps make this a higher quality free-help community
Posted 06 May 2006 - 11:12 AM
you know that there IS a *solved* button you can push. Or are you afraid someone out there is going to steal your code.
[/quote]Actually there is no solved button no more. The solved button got removed when the forum got upgraded just before Xmas.
Also I'm closing this thread.
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