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PHP Beginner- Simple Form Problem


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#1 MattC

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Posted 15 May 2006 - 03:21 AM

Hello,
I've been dealing with website for quite a while, but only now am getting into PHP coding. I copied some code from Jason Gilmore's book about inserting data into a mySQL database. Basically, I have two files:

insert.php


<form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post">
<P>
Product ID: <input type="text" name="productid" size="8" maxlength="8" value="" />
</p>
<p>
Name: <input type="text" name="name" size="25" maxlength="25" value="" />
</p>
<p>
Price: <input type="text" name="price" size="6" maxlength="6" value="" />
</p>
<p>
Description: <textarea name="description" rows="5" cols="30"></textarea>
</p>
<p>
<input type="submit" name="submit" value="Submit!" />
</p>
</form>

test.php

<?php


    //If submit button has been pressed
    if (isset($POST['submit']))
    {

         //Connect to the server and select the database
        $linkID = @mysql_connect("localhost","username","password")
            or die("Could not connect to my SQL server");
        @mysql_select_db("sqltesting") or die("Could not connect to database");

        //Retrieve the posted product information.
        $productid = $_POST['productid'];
        $name = $_POST['name'];
        $price = $_POST['price'];
        $description = $POST['description'];

        //Insert the info into the prodict table
        $query = "INSERT INTO product SET productid='$productid', name='$name', price='$price', description='$description'";

        $result = mysql_query($query);

        //Display the appropriate message
        if ($result) echo "<p>Product info has been entered.</p>";
        else echo "<p>You screwed up.</p>";

        mysql_close();
        }

//Include the insertion form
include "insert.php";

?>

I bring up test.php in the browser, fill it out and hit Submit. This brings me right back to the form with no data entered in it at all. Even if I setup the wrong database information, I get no error messages about connecting. Am I going about this the wrong way? I've checked the code over many times and can't find anything wrong with it.

Thank you.

#2 mb81

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Posted 15 May 2006 - 03:27 AM

Check your isset() function, it says $POST, not $_POST;

#3 .josh

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Posted 15 May 2006 - 03:29 AM

if you are trying to get the form info from insert.php to test.php you need to change your from action to 'test.php' instead of $PHP_SELF

also you for got the underscore in $POST should be $_POST here (in addition to the one mentioned above):

$description = $[!--coloro:red--][span style=\"color:red\"][!--/coloro--]_[!--colorc--][/span][!--/colorc--]POST['description'];

also this:

$query = "INSERT INTO product SET productid='$productid', name='$name', price='$price', description='$description'";

should be this:

$query = "INSERT INTO product (productid, name, price, description) VALUES '$productid','$name', '$price','$description')";

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#4 MattC

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Posted 15 May 2006 - 08:26 PM

Okay, the $_Post problem proved to be it. I need to be more thorough next time. Thanks for the help.

#5 ryanlwh

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Posted 15 May 2006 - 08:42 PM

Crayon, the INSERT INTO () VALUES () and INSERT INTO SET both work. the second is a variant of the INSERT query which most people do not know of. If you're building a query for UPDATE and INSERT, using hte second variant provides a benefit because you can declare a string for the SET part to be used twice.
Please use EDIT * 100...
Please use
or [php] * 1000...

PLEASE READ THE POSTED SOLUTIONS CAREFULLY * 1000000...




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