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loren646

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  1. Thanks. I'm going to do some reading up on this right now.
  2. just text data. I can either put it in a mysql database or excel. it doesn't matter. i just want to automate it - rather than do it manually.
  3. http://a810-bisweb.nyc.gov/bisweb/bispi00.jsp example (on row 1 of property search): Select "manhattan" Input "22" "west 11 st" Click "GO" ---- Click "complaints" then click each complaint and copy the disposition i.e. "01/26/2004 - A9 - ECB & BUILDINGS VIOLATIONS SERVED"
  4. I'm sure it's possible. I want to go to a website. Input values then copy and paste data it found from that search. Not even sure where to start.
  5. list of supervisors for each building is echoed in a text box. Right now they get echoed each time for every single apartment in the building. I only want it to show up once per building. maybe an if statement saying if supervisors name has been echoed already for that building do not output again.
  6. got three columns Table: Rentals: Columns: house number, street, owner. what's the coding? "SELECT owner FROM Rentals" Not sure what to write so i don't select duplicate owners. or is it better to select all and then when echo don't echo the duplicates?
  7. is there a way to do this without adding it to the url?
  8. ANSWERED. It adds to the previous variable. appends.
  9. $variable.= ??? why does the variable have the "." ? what does that mean?
  10. while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['hotel'] . "</td>"; echo "<td>" . $row['hotelnum'] . "</td>"; echo "<td>" . $row['price'] . "</td>"; echo "<td align='center'>" . $row['bedroom'] . "</td>"; echo "<td>" . $row['descrip'] . "</td>"; echo "<td>" . $row['level1'] . "</td>"; echo "<td>" . $row['level2'] . "</td>"; echo "<td>" . $row['notes'] . "</td>"; ?> <td><A HREF="viewhotelnum.php" onClick="return popup(this, 'notes')">view</A></td> <?php echo "</tr>"; } echo "</table>"; mysql_close(); I want to send the $row['prim'] to the link viewhotelnum.php. This way when they click the link the viewhotelnum.php I can display the photos for that particular hotel room.
  11. it's more than just the space. i tried changing the folder from 40 Allen to 40Allen it still outputs nothing. okay... i removed the first / and it seems to work. SOLVED
  12. <img src="/pics/Dan/40 Allen/4/201232313_33.jpg" alt="40allen" width="400" height="400"><br> <?php $dir = "/pics/Dan/40%20Allen/4/*"; // Open a known directory, and proceed to read its contents foreach(glob($dir) as $file) { echo "filename: $file : filetype: " . filetype($file) . "<br />"; } $files = glob("/pics/Dan/40 Allen/4/*.{jpg,gif,png}", GLOB_BRACE); echo "yo yo".$files[0]; ?> I'm trying different ways using %20 and without using %20. Nothing seems to come up. The html works on top. It only prints the picture from the html and the "yo yo"
  13. In case anyone else is having this problem. For future reference. I deleted all the white space. I guess the formatting caused problems. SOLVED.
  14. <?php // Connects to your Database error_reporting(E_ALL); ini_set("display_errors", 1); mysql_connect("localhost", "xxxx", "xxxx") or die(mysql_error()); mysql_select_db("xxxx") or die(mysql_error()); //Checks if there is a login cookie if(isset($_COOKIE['ID_my_site'])) //if there is, it logs you in and directes you to the members page { $username = $_COOKIE['ID_my_site']; $pass = $_COOKIE['Key_my_site']; $check = mysql_query("SELECT * FROM users WHERE username = '$username'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if ($pass != $info['password']) { } else { header("Location: members.php"); } } } //if the login form is submitted if (isset($_POST['submit'])) { // if form has been submitted // makes sure they filled it in if(!$_POST['username'] || !$_POST['pass']) { die('You did not fill in a required field.'); } // checks it against the database // if (!get_magic_quotes_gpc()) { // $_POST['email'] = addslashes($_POST['email']); // } $check = mysql_query("SELECT * FROM users WHERE username = '".$_POST['username']."'")or die(mysql_error()); //Gives error if user dosen't exist $check2 = mysql_num_rows($check); if ($check2 == 0) { die('That user does not exist in our database. <a href=areg.php>Click Here to Register</a>'); } while($info = mysql_fetch_array( $check )) { $_POST['pass'] = stripslashes($_POST['pass']); $info['password'] = stripslashes($info['password']); $_POST['pass'] = md5($_POST['pass']); //gives error if the password is wrong if ($_POST['pass'] != $info['password']) { die('Incorrect password, please try again.'); } else { // if login is ok then we add a cookie $_POST['username'] = stripslashes($_POST['username']); $hour = time() + 3600; setcookie(ID_my_site, $_POST['username'], $hour); setcookie(Key_my_site, $_POST['pass'], $hour); //then redirect them to the members area header("Location: members.php"); } } } else { // if they are not logged in ?> <form action="<?php echo $_SERVER['PHP_SELF']?>" method="post"> <table border="0"> <tr><td colspan=2><h1>Login</h1></td></tr> <tr><td>Username:</td><td> <input type="text" name="username" maxlength="40"></td></tr> <tr><td>Password:</td><td> <input type="password" name="pass" maxlength="50"> </td></tr> <tr><td colspan="2" align="right"> <input type="submit" name="submit" value="Login"> </td></tr> </table> </form> <?php } ?> added error checking. added "//" before the email part (not sure why that's in there.) These are now the current errors: Notice: Use of undefined constant ID_my_site - assumed 'ID_my_site' in login.php on line 60 Warning: Cannot modify header information - headers already sent by (output started at login.php:1) in login.php on line 60 Notice: Use of undefined constant Key_my_site - assumed 'Key_my_site' in login.php on line 61 Warning: Cannot modify header information - headers already sent by (output started at login.php:1) in login.php on line 61 Warning: Cannot modify header information - headers already sent by (output started at login.php:1) in login.php on line 65
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