LTMH38
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it works now... thanks a lot
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I've sent the form data to AJAX2.php properly indicating JSON data in this page and I've used the callback function to insert the data back in the page AJAX1.php with a jquery html method but the page display an alert with a failed request. $.ajax({ url: "AJAX2.php", type: "POST", data: $('form').serialize, dataType: "json", success: function(data) { $('#display').html(data); }, error: function(jqXHR, data ) { alert ('Ajax request Failed.'); } }); <body> ... <div id="display"> </div> </body> <?php header('Content-Type: application/json'); $variable = $_POST['var']; echo json_encode($variable); ?> Why does this happen?
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Hi. I've been learning ajax with jquery and I am struggling to work out how to pass PHP variable between two PHP pages. I started with a simple form: <!DOCTYPE HTML> <html lang=""> <head> <meta charset="UTF-8"> <title>FORM1</title> </head> <body> <div class="container"> <?php for($a = 0; $a < 3; $a++): ?> <form action="FORM2.php" method="post"> <input type="hidden" name="var" value="<?php echo $a; ?>"> <input type="submit" name="submit" value="Index <?php echo $a; ?>"> </form> <?php endfor; ?> </div> </body> </html> <?php header('Content-Type: text/html; charset=utf-8'); $variable = $_POST['var']; echo $variable; ?> How can I do the same without page refresh using ajax? I have tried using json encoder but I haven't been successful. <!DOCTYPE HTML> <html lang=""> <head> <meta charset="UTF-8"> <title>AXAX1</title> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script> <script> $(document).ready(function(){ $('form').submit(function(e) { e.preventDefault(); $.ajax({ url: "AJAX2.php", type: "POST", dataType: "json", success: function(result) { alert(data); }, error: function(jqXHR, data ) { alert ('Ajax request Failed.'); } }); }); }); </script> </head> <body> <div class="container"> <?php for($a = 0; $a < 3; $a++): ?> <form action="AJAX2.php" method="post"> <input type="hidden" name="var" value="<?php echo $a; ?>"> <input type="submit" name="submit" value="Index <?php echo $a; ?>"> </form> <?php endfor; ?> </div> </body> </html> <?php header('Content-Type: text/html; charset=utf-8'); $variable = $_POST['var']; echo json_encode($variable); ?>
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In the same directory I have two php documents and a folder called "gallery". This folder contain a lot of images files. I send a variable from the first page with the folder name. In the second page I open the directory and read directory content with glob function. I have tried to send images back to the first page again but images do not appear properly. I take a tutorial from this page: http://www.kvcodes.com/2013/12/get-all-images-from-a-directory-dynamically-php-jquery-ajax/ gallery.php <!DOCTYPE HTML> <html lang=""> <head> <meta charset="UTF-8"> <title>Gallery</title> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script> <script> //start jquery $(document).ready(function(){ //submit from form $('form').submit(function(e) { e.preventDefault(); //start ajax with jquery $.ajax({ url: "directory.php", type: "POST", data: {'var': $('form input[name="var"]').val()}, dataType: "HTML", success: function( data ) { $('body').append(data); }, error: function(jqXHR, data ) { alert ('Ajax request Failed.'); } }); }); }); </script> </head> <body> <div class="content"> <p> Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nam felis mi, pellentesque at scelerisque eu, consectetur quis felis. Aliquam mollis </p> </div> <div class="form"> <!--directory variable--> <?php $a = "gallery"; ?> <form action="directory.php" method="post"> <input type="hidden" name="var" value="<?php echo $a; ?>"> <input type="submit" name="submit" value="gallery"> </form> </div> <!--to display ajax result with colorbox--> <div class="gallery"> </div> </body> </html> directory.php <!DOCTYPE HTML> <html lang=""> <head> <meta charset="UTF-8"> <title>image directory</title> </head> <body> <?php //get the path of images directory $variable = $_POST['var']; $img_dir = $variable . "/"; //loop to bring all images inside directory foreach(glob($img_dir . '*.jpg') as $images) { echo '<img src="'.$img_dir.$images.'">'; } ?> </body> </html> Any guidance would be appreciated. Thanks in advance.
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Converting arrays into a multi-dimensional array
LTMH38 replied to LTMH38's topic in PHP Coding Help
Thank Psycho and Barand. I had tried with array_push: array_push ($DIR, $file); to display array values I had tried with a pair of loops: for($d = 0; $d <= count($DIR); $d++) { for($e = 0; $e <= count($DIR[$d]); $e++) { echo $DIR[$d][$e] . "<br>"; } } Unfortunately array values are not properly show. Also, a notice indicate undefined offset . -
I have a list of folder names like 1, 2, 3... Each folder has some .jpg files. I get a list of all including files from this directories with two glob functions dynamically. I store a list of directory paths and filenames into two separates arrays called $DIR[] and $files[]. How can I convert this arrays to one multidimensional array and how can I get values in each dimension with this array? <?php //FOLDERS //create array for each directory $pathDIR = "dirname/"; $DIR = Array( ); //store directory names into an array with foreach foreach (glob($pathDIR . '/[0-30]*', GLOB_ONLYDIR) as $dirname) { $DIR[] = $dirname; } //display path directories for($a = 0; $a < count($DIR); $a++) { echo $DIR[$a] . "<br>"; } //FILES //create array for each directory $pathFILE = Array(); //create array for files $files = Array(); //loop start for($b = 1; $b <= count($DIR); $b++) { $pathFILE[$b] = "dirname/" . $b . "/"; //store files in array with foreach foreach(glob($pathFILE[$b] . '*.jpg') as $filename) { $files[] = $filename; } } //display files for($c = 1; $c <= count($files); $c++) { echo $files[$c-1] . "<br>"; } //convert arrays to multidimensional array array_push ($DIR, $files); ?>