scadran
Members-
Posts
12 -
Joined
-
Last visited
Never
About scadran
- Birthday 05/24/1985
Contact Methods
-
Website URL
http://www.emuchix.com
-
Yahoo
scadran2000
Profile Information
-
Gender
Male
-
Location
Famagusta - Cyprus
scadran's Achievements
Newbie (1/5)
0
Reputation
-
what am i including? nothing really .... The page is displayed completely and correctly ... but i need to know why should i have that warning at the very top of the page!? is there something wrong with this part? echo $cart; $cart = $_SESSION['cart']; require_once('inc/functions.php'); include('config.php'); ?> cause this is the only part which i ve included and then recieved the warning!?
-
I am not sure what u mean ... but if u mean the philosophy.php file, then I ve opend the file via the browser ... I am running it on my own server.
-
Hi guys My codes arw as follow: <?php // Start the session session_start(); // Process actions $cart = $_SESSION['cart']; $action = $_GET['action']; switch ($action) { case 'add': if ($cart) { $cart .= ','.$_GET['id']; } else { $cart = $_GET['id']; } break; case 'delete': if ($cart) { $items = explode(',',$cart); $newcart = ''; foreach ($items as $item) { if ($_GET['id'] != $item) { if ($newcart != '') { $newcart .= ','.$item; } else { $newcart = $item; } } } $cart = $newcart; } break; } $_SESSION['cart'] = $cart; ?> <html> <head> <?php echo $cart; $cart = $_SESSION['cart']; require_once('inc/functions.php'); include('config.php'); ?> <meta http-equiv="Content-Type" content="text/html; charset=windows-1256"> <link rel="stylesheet" type="text/css" href="style.css"> <title>جزئیات سبد خرید شما</title> <script type="text/javascript" language="JavaScript1.2" src="_pgtres/stmenu.js"></script> </head> <body background="images/fa_mainbg.gif"> ........... Why do i recieve tis error? Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at C:\wamp\www\pangaan\philosophy.php:4) in C:\wamp\www\pangaan\philosophy.php on line 5
-
any idEA?
-
Hi guys I am about to do two different actions on the same form with the same data. What I have done so far is that First: I have created two different submit button with the same name and different value <input type="submit" value="Publish Invoice" name="flag"> <input type="submit" value="Summary Report" name="flag"> in the action page I have got the data with POST and check the status of the submit value: <?php $flag = $_POST['flag']; if ($flag=='Publish Invoice') include('publish.php'); else { include('summary.php');} ?> when i press publish invoice buttomn i recieve the following error: Parse error: syntax error, unexpected '}' in C:\wamp\www\Pierra Invoice\publish.php on line 99 Just in case if you need the publish.php page, here it is: include('config.php'); $result = mysql_query("SELECT * FROM temp") or die(mysql_error()); $row = mysql_fetch_array($result); $cnt=1; $new_no = $row[6]; while ( $cnt <= $row[5] ) { $cd='a'.$cnt; $code = $_POST[$cd]; $tyre_arr = mysql_query("select * from tyre where code='$code'") or die(mysql_error()); $tyre = mysql_fetch_array($tyre_arr); ?> <div align="center"> <center> <table border="0" cellpadding="0" cellspacing="0" style="border-collapse: collapse; border-style: double; border-width: 3" bordercolor="#111111" width="1024" height="430"> <tr> <td width="100%" dir="rtl" height="430"> <img border="0" src="PIERRA%20LOGO.jpg" width="93" height="88" align="right"><div align="left"> <table border="0" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#111111" width="30%" > <tr> <td width="50%"><font face="B Compset" size="4"> شماره فاکتور:</font></td> <td width="50%"><font face="B Compset" size="4"> <?php if (strlen($new_no)==1) echo "0000".$new_no; elseif(strlen($new_no)==2) echo "000".$new_no; elseif(strlen($new_no)==3) echo "00".$new_no; elseif(strlen($new_no)==4) echo "0".$new_no; else echo $new_no; ?> </font></td> </tr> <tr> <td width="50%"><font face="B Compset" size="4"> تاریخ: </font></td> <td width="50%"><font face="B Compset" size="4"><?php echo $row[2]."/".$row[3]."/".$row[4]?></font></td> </tr> </table> </div> <p align="center"><font face="B Jadid" size="5">فاکتور سفارش</font></p> <p> <font face="B Compset" size="4"> نام خریدار: <?php echo $row[1]?></font></p> <div align="center"> <center> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#111111" width="90%" id="AutoNumber3" height="52"> <tr bgcolor="#C0C0C0"> <td width="20%" align="center" height="19"><b><font face="Tahoma">کد پیرا</font></b></td> <td width="20%" align="center" height="19"><b><font face="Tahoma">سایز</font></b></td> <td width="20%" align="center" height="19"><b><font face="Tahoma"><span lang="en-us"> Serial Number</span></font></b></td> <td width="20%" align="center" height="19"><b><font face="Tahoma"><span lang="en-us"> Brand</span></font></b></td> <td width="20%" align="center" height="19"> <p dir="ltr"><b><font face="Tahoma"><span lang="en-us"> Price (Rial)</span></font></b></td> </tr> <tr> <td width="20%" align="center" height="32"> <font face="Tahoma" size="2"><span lang="en-us"><?php echo $tyre[0] ?></span></font></td> <td width="20%" align="center" height="32"><span lang="en-us"><p dir="ltr"> <font face="Tahoma" size="2"><?php echo $tyre[1] ?></font></span></p></td> <td width="20%" align="center" height="32"><span lang="en-us"> <font face="Tahoma" size="2"><?php echo $tyre[2] ?></font></span></td> <td width="20%" align="center" height="32"><span lang="en-us"> <font face="Tahoma" size="2"><?php echo $tyre[3] ?></font></span></td> <td width="20%" align="center" height="32"><span lang="en-us"> <font face="Tahoma" size="2"><?php echo number_format($tyre[4]) ?></font></span></td> </tr> <tr> <td width="80%" align="center" height="32" colspan="4"> <p align="right"><font face="Tahoma" size="2"><span lang="en-us"> </span>سه درصد عوارض فروش</font></td> <td width="20%" align="center" height="32"><?php echo number_format(0.03*$tyre[4]) ?></td> </tr> <tr> <td width="80%" align="center" height="32" colspan="4"> <p align="right"><font face="Tahoma" size="2"> </font> <font face="Tahoma">جمع کل:</font></td> <td width="20%" align="center" height="32" bgcolor="#CCCCCC"><?php echo number_format(0.03*$tyre[4]+$tyre[4]) ?></td> </tr> </table> </center> </div> <p> </p> <p > <br> اداره فروش </font> </p> <p align="left"> </p> </td> </tr> </table> </center> </div> <p align="center"> --------------------------------------------------------------------------------------------------------------</p> <?php $new_no = $row[6]+$cnt; $mosi = mysql_query("UPDATE temp SET last_invoice='$new_no' WHERE id='0'") or die(mysql_error()); $cnt = $cnt+1; } ?> tell me what is wrong now? ???
-
Hi guys I have a page in which i will ask the user to enter number of people. according to their answer I will create textbox the same amount as they gave the answer. they complete the text box and i want to send it to the other page by POST. how can I take them in a while loop by the next page? Can someone help me here are my codes: within the page which create the nested textboxes: $counter = 1; while ( $counter <= $no ) { echo "<input type=\"text\" name=\"".'a'."$counter\" size=\"6\"> "; $counter = $counter + 1; } ?> within the page which i want to recive them: $result = mysql_query("SELECT * FROM temp") or die(mysql_error()); $row = mysql_fetch_array($result); $cnt=1; $new_no = $row[6]; while ( $cnt <= $row[5] ) { $cd='a'.$cnt; $code = $_POST['$cd']; echo $code; $tyre_arr = mysql_query("select * from tyre where code='$code'") or die(mysql_error()); $tyre = mysql_fetch_array($tyre_arr); ?> I guess there should be something wrong with this line: $code = $_POST['$cd']; any idea?
-
I am getting a date entry through POST by a form byt the format enetered by the user is 'dd/mm/yy' .... how could i use MYSQL PHP syntax to insert the proper format as it is default in the table in my database. which function is it? Rgards
-
hey guys I have just designed a BD. there are companies with auto increament which are integer. When I try to populate it after i tool value from another form and try to insert it into a table i recieve an error! I don't ask the companyID value from user as it is auto increament. Don't tell me to put NULL for that entry as it didn't work as well! here are codes: <?php include 'config.php'; $comp_name = $_POST['companname']; $desc = $_POST['desc']; $telephoneno = $_POST['tel']; $own = $_POST['owner']; $sql = "INSERT INTO company ( description , telephoneno , owner , compname, compid ) VALUES ($desc, $telephoneno, $own, $comp_name, NULL)"; $result = mysql_query($sql) or die('Query failed. ' . mysql_error()); header('location: panel.php'); ?> Any idea what should i do to not recieve Query failed. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near .... Thanks Guys waiting for ur answers!
-
so how about the rest of the file content which needs to be written in the same file? Shall I open the <?php tag again? any btw it didn't solve the problem... same error occurs! more idea?
-
guys, here is the simple code i used to create a RSS but this error appears Parse error: syntax error, unexpected T_STRING in C:\wamp\www\Journalness\rss.php on line 11 here is the code: <?php $connection = mysql_connect("localhost", "root", "123"); mysql_select_db("emu", $connection); $select = "SELECT `id`, `title`, `entry_text`, `date` FROM `emu_entries` ORDER BY `id` DESC LIMIT 5"; $query = mysql_query($select) or die(mysql_error()); $file = fopen("rss.xml", "w") fwrite($file, "<?xml version="1.0"?> <rss version="2.0"> <channel> <title>The Shadow Fox Feed</title> <link>http://www.shadow-fox.net</link> <description>Feed Description</description> <language>en-us</language>"); while($array = mysql_fetch_array($query)){ extract($array); $content = htmlentities($entry_text); fwrite($file, "<item> <title>$title</title> <link>http://localhost/Journalness/past.php?id=$id</link> <description>$content</description> </item>"); } //end of while loop fwrite($file, "</channel></rss>"); fclose($file); ?> I am sure there s no problem with my database connection and the file previlage. Regards Mohsen
-
Hey guys I have just installed PHP with MySql with Apache server. I have installed PHPMyAdmin too. I could successfully enter to PHPmyAdmin and login and use it properly. But when I code a PHP source myself and call it from localhost, nothing displays. I have debugged the php file in Zend Studio. It gave me this error: [b]"Debug Error: ..\config.php line 11 - Call to undefined function mysql_connect()"[/b] To tell you that I am sure about the correctness of my codes, I have paste them here: [color=red] [font=Verdana]$link = mysql_connect($db_host, $db_user, $db_pass); if (!$link) { die('Could not connect: ' . mysql_error()); } echo 'Connected successfully';[/font][/color] What do you think the problem is? Can anybody help???