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Devil_Banner

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  1. Either English or French, which I can retranslate for you. Other than that ... maybe some dutch as well
  2. Thanks alot for helping me out on that one. Say I wanted to improve and have the user choose in a first dorpdownlist, and by doing so have it populate the second dropdownlist with stuff relevant to the first choice? Lemme explain : Say the user chooses "printer" in the first dropdownlist (populated by "ArticleType" column (Article.ArticleType)), then I would want the second dropdownlist (Article.ArticleBrand) to display choices like HP, Epson, and so on... Is this easy to do ? I mean, dynamically  ? Thanks very much for you guys' time :-)
  3. Great !!! I guess that was an easy one, wasn't it ? :) Lotsa thanks, gterre. It got me stuck for a while.
  4. Hi, I'm new at this myself.. ;but maybe you should try a "require" instead of "include" for your variable file Hope this helps.
  5. Hi there, I have this really dumb problem with my query. I have to admit i'm a newbie, hence my stupid problem. I Use MySQL 5. (Easyphp 1.8 ) I have a table which has a column named ArticleModel. I Have four entries in this table. My goal is to select the entries in this table and output them into a dropdown list. For example, I want the list to contain LaserJet 4000 Deskjet 1200 Latitude D515 Cisco 2950 series I can't get further than having 4 times 'array' written in my dropdown list. I have managed to get the first one (Laserjet 4000) to get into the list, but I can't figure out how to loop so it continues to fill my list... Here's my code: [color=green]$conn[/color] = [color=blue]mysql_connect[/color]([color=green]$dbHost[/color], [color=green]$dbUser[/color], $dbPassword) or die([color=orange]'DB connexion error'[/color]); [color=blue]mysql_select_db[/color]($dbName) or die ([color=orange]"DB not reachable"[/color]); //query [color=green]$sql[/color] = [color=orange]"SELECT * FROM article "[/color]; [color=green]$query[/color] = [color=blue]mysql_query[/color]([color=green]$sql[/color]); if (![color=green]$query[/color]) {               // error handler               echo [color=orange]'Query failed. SQL: '[/color], [color=green]$sql[/color], [color=orange]'<br />Error # '[/color], [color=blue]mysql_errno()[/color], [color=orange]' Error msg: '[/color], [color=blue]mysql_error()[/color];               exit;              } //end of query [color=green]$row[/color] = [color=blue]mysql_fetch_array[/color]([color=green]$query[/color]); [color=green]$item[/color] = [color=green]$row[/color][[color=orange]'ModeleArticle'[/color]]; echo "<option value=\"[color=limegreen]$item[/color]\">[color=green]$item[/color]</option>"; Now, I suppose that before the next to last line of code, there should be a loop, but like I said : can't figure out how... Thanks alot for helping me out.
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