amazingpatel

*bump* Does anybody have any ideas?

Does anybody know why a user can type a joke into the form but not copy and paste a joke into the form? If a joke is pasted into the form it somehow is enetered as blank.

The user is posting a joke. It works when they type it in, it doesn't work when they copy and paste.

Hello,       Here is the code: <?php include("jheader.php"); ?> <table cellpadding=1 border=0 cellspacing=0 width=458> <tr> <td bgcolor=<?php printf($sitecolor); ?> align=center> <font size="3" face="Arial, Helvetica, sans-serif"><b>Add Joke</b></font><br> <table bgcolor=#CECECE cellpadding=1 border=0 cellspacing=0 width=100%> <tr> <td align=center> <FONT SIZE=2> <center> <?php if (logincheck($uid, $upwd)) { ?> <form enctype="multipart/form-data" action=savejoke.php method=post> <table cellpadding=5 cellspacing=0> <tr> <th colspan=2><font size=2 face='Arial, Helvetica, sans-serif'>Enter the title for your Joke</font></th> </tr> <tr> <td colspan=2 align=center><input type=text name=joketitle size=60></td> </tr> <tr> <th colspan=2><font size=2 face='Arial'>Enter the Joke</font></th> </tr> <tr> <td colspan=2><textarea name=joke rows=20 cols=50></textarea> </tr> <tr> <th colspan=2><font size=2 face='Arial'>Select a Categories</font></th> </tr> <tr><td colspan=2> <?php $sql = "select * from categories order by category"; $result = mysql_query($sql ,$db); $newrowcount = 0; printf("<table><tr>"); if ($myrow = mysql_fetch_array($result)) { do { if ($newrowcount == 4) { $newrowcount = 0; printf("</tr>"); printf("<tr>"); } printf("<td><font size=2 face='Arial'><input type=radio name=catid value=%s> %s</font></td>", $myrow["catid"], $myrow["category"]); $newrowcount++; } while ($myrow = mysql_fetch_array($result)); } for ($c = $newrowcount; $c < 4; $c++) { printf("<td></td>"); } printf("</tr></table>"); ?> </td></tr> <tr> <td colspan=2 align=middle> <br> <input type=reset value=Reset>     <input type=submit value=Submit> </td> </tr> </table> </form> <?php } else { printf("<font size=2 face='Arial'><br>You need to be logged in before you can add a joke</font>"); } ?> </center> </FONT> </td> </tr> </table> </td> </tr> </table> <?php include("jfooter.php"); ?>

Hello,       I have a form on a webpage, when a user types something into the form and clicks submit the users comments are passed through to the mysql db, but when a user copies and pastes text into the form the data is not passed through to the mysql db. Any help or advice would be much appericated. Thanks in advance.