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Tmic

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  1. can\'t test it but maybe if you change c.cat_id = 1 to c.cat_id in (1,2,3,..)
  2. sry the second * must be % ofcourse this works on my system but I don\'t use phpadmin
  3. more like this: select * from hotels where \' *j%\' in (hotelname,hotelcountry,hoteladdress);
  4. THX mtoynbee It works except for the last line like you said. I did it like I normally do while($row = mysql_fetch_array($result)){ $max = $row[\'max(nr)\']; } But I still think there must be a better way as there is only one result with max.
  5. Sorry for not being very clear. When I do the following: select max(nr) from table_test; in mysql (via dosprompt) I get the result (f.i. 9) now I try to do the same in php and normally I would do something like this: $select = \"select nr from table_test\"; $result = mysql_query($select); while($row = mysql_fetch_array($result)){ echo $row[\'nr\']; } but now its not nr but max(nr) but when I change all \'nr\' to \'max(nr)\' it doensnt seem to work. I would like to now how I can get the value of max(nr) into a php variable. I think there is an easy way to do this but I\'m not seeing it.
  6. select max(nr) from tablename; but I want to get the max(nr) in php. How can I do this?
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