flashx
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Posts posted by flashx
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Hi guys,
I have a bit of a problem,
Im using php and mysql and have succeded in storing variables inside of a URL:
echo "<a href='report.php?id=$varmemberid&colour=$varcolour'>test</a> ";
i retrieve varmemberid and colour from the mysql database:
$tbl_name = "members"; mysql_select_db($db_name) or die (mysql_error()); $query="SELECT * FROM $db_name ORDER BY `members`.`the_members` ASC"; $result=mysql_query($query); $num=mysql_numrows($result); $i=0; while ($i < $num) { $varmemberid=mysql_result($result,$i,"member_id"); $varcolour=mysql_result($result,$i,"colour");
that works all fine and dandy for numbers eg: "123" however if i go to insert a member id of "123t" i get this error:
Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 12 in /home/flashx/public_html/login/report-header.php on line 47
im guessing it has something to do with the 'int' in this line:
$memberid = (int) $_GET['memberid'];
how do i fix this?
Cheers
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Help!!
in MySQL Help
Thanks Buddski,
Im actually here because I have spent the last few days trying to nut it out but cant actually get it working! I need some help with a good clean example, would you (or anyone else) recommend any good tutorials on dynamically creating textboxes and saving back into a mysql database?
Cheers
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Help!!
in MySQL Help
Hi guys,
does anyone know how to dynamically create a textfeild and fill it with a specific cell data from mysql?
also is there anyway to have it that it is updatable when i press a button to save it?
cheers
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Hi ladies and gents,
Im new to PHP & mysql, so please go easy on me
I have connected my mysql database up to my php webpage but im having a bit of trouble gettin my head round dynamically displaying and updating a row of fields using input textboxes.
currently i have this:
$i=0; while ($i < $num) { $myname=mysql_result($result,$i,"firstname"); echo "<input type='text' name='name' value='$myname'><br/>"; $i++; }
(the above displays all names in the firstname field)
my fields are as follows:
firstname, lastname, age, gender etc
so i guess my question is, how do i create a script that runs through each row and dynamically displays each field in a textbox which in turn is updatable by clicking a save button?
Any help would be much appreciated.
Cheers
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Hi grlayouts,
thanks for your reply. that seems to work, thanks heaps
Cheers
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Hi guys,
im needing to grab information out of a mysql database field called "clientname" thats inside a table called "clients"
how do i retrieve the clients name in html and display it?
heres what i have so far, am just needing the code to retrieve...
$host = localhost; $dbuser = user; $dbpass = pass; $dbname = mydb; $connection = mysql_connect($host, $dbuser, $dbpass); $db = mysql_select_db($dbname, $connection); // code to retrieve a particular clients details
Cheers,
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gizmola you rock my world!!
thanks for pointing that out! its all working now, much appreciated!!
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hi there,
im new to all this stuff, so im guessing this is quite easy to fix.
i trying to get php to create a new user in a form in myphpadmin, however it seems to only accept numbers, does anyone know why?
here is my code for php:
<?php //begin $host = localhost; $dbuser = user; $dbpass = pw; $dbname = dbname; $connection = mysql_connect($host, $dbuser, $dbpass); $db = mysql_select_db($dbname, $connection); //grab data from form $name = $_POST[username]; $pass = $_POST[password]; $pass_conf = $_POST[pass_conf]; $email = $_POST[email]; if($name == false || $pass == false || $pass_conf == false || $email == false){ echo "Please fill in all required fields."; }; if($pass != $pass_conf){ echo "Passwords do not match"; }else{ $connection = mysql_connect($host, $dbuser, $dbpass); $db = mysql_select_db($dbname, $connection); $sql = "INSERT INTO user (username,password,email) VALUES ($name, $pass, $email)"; $result = mysql_query($sql); echo "Thank you for your registration to YOURSITENAME.com"; }; ?>
and here is my form:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form name=reg action=do_reg.php method=post> Username: <input name=username type=text /><br /> Password: <input type=password name=password /><br /> Confirm: <input type=password name=pass_conf /><br /> Email: <input type="text" name=email /><br /> <input type="submit" value='Register' /> </form> </body> </html>
any help would be great!
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Hi guys,
this is my first post, and im needing some help with email and variables in php.
when i save this out it works:
<?php $test = "hi there"; mail('myemail@mythingy.com.au','test subject', 'This is a test'); ?>
but as soon as i add variable into the mix it doesnt work...
<?php $email = "myemail@mythingy.com.au"; mail($email,'test subject', 'This is a test'); ?>
any clues?
URL variable problem
in PHP Coding Help
Posted
oh you rock! thanks for your help, that worked