Hello,
I have created two tables, one called 'posts' and the other 'selected_pic'.
The idea is to have a table of posts that gets stored with an ID that references the image in the 'selected_pic' table. From what i have gathered, using Foreign keys is probably the best way y do this? If theres something easier, then please let me know.
However when i try to make a post on the web page "Cannot add or update a child row: a foreign key constraint fails " comes up and thus fails to insert into the table.
This is what i have set up so far..
TABLE : selected-pic
'pic_id' - int(11) - NOT_NULL - auto_increment
'username' - varchar(32) - NOT_NULL
'imagelocationpic' - varchar(100) - NOT_NULL
Primary Key - 'pic_id'
Table : posts
'posts_id' - int(11) - NOT_NULL - auto_increment
'pic_id' - int(11) - NOT_NULL
'username' - varchar(11) - NOT_NULL
'text' - varchar(100) - NOT_NULL
'date' - date - NOT_NULL
'time' - int(11) - NOT_NULL
'up' - int(11) - NOT_NULL
'down' - int(11) - NOT_NULL
'profile_pic' - varchar(100) - NOT_NULL
Primary Key - 'posts_id'
Index key - 'pic_id'
*Here i have set the 'pic_id' from the 'posts' table to reference the 'pic_id' in the 'selected_pic' table.
PHP & Mysql code on page.
<?php
$id=$_SESSION['username'];
$time=time();
$date=date("Y-m-d");
if($_POST['post'])
{
//get the data
$text=$_POST['text'];
$image=$_POST['profile_pic'];
//check for existance
if ($text)
{
//insert data
include ("connect2.php");
$time=time();
$insert=mysql_query("INSERT INTO posts VALUES('', '', '$id','$text','$date', '$time','','','$image')") or die(mysql_error());
echo "";
}
else echo "Please fill out the text field";
}
echo"
<br>";
?>
Thanks in advance!
Dave