esoteric

No, bit of a pain

I got a reply from my host, he said he new the problem and has to reset my sessions, needless to say that didn't do anything as i expected but he also said But im not sure what he means, how would i change this to make that change, anything i try give me 'ini_set() [function.ini-set]: SAFE MODE Restriction in effect', safe mode is off. ini_set('session.save_path', '/var/www/vhosts/xxxx.co.uk/httpdocs/tmp');

Is this the info you wanted? i had to download a addon for firefox to see it name - PHPSESSID host - .xxxxxxxxx.co.uk content - 7qpi4boe4n5rf26hha1tqh45p5 path - / and the host does have the . at the start. I deleted all other cookies, this is the only one i have from a fresh login attempt. I cant test it from another domain because i would need to shift a whole load of script about to do it, but if need to in order to find the problem i will?

oh and i created the folder at 'xxxxx.co.uk/httpdocs/tmp' and gave it full permission (777)

The cookie name is my website name without the www. (so domain.co.uk) the top of my php pages looks like this <? ini_set('session.save_path', '/var/www/vhosts/xxxxx.co.uk/httpdocs/tmp'); ini_set('session.cookie_domain', '.xxxxx.co.uk'); session_start(); I dont have access to the php.ini which i was surprised about, they wont let me change anything, i tried adding it to my htaccess it just stopped me logging in at all. session.auto_start = Off session.cookie_path = / Thank you

I understand the search engine problem but it isn't really an option, my site has been set up like this for a while and changing it now would make all paperwork and existing users links etc.. invalid. We also have business cards which point to specific sub domains so i'm not too worried about search engines. thanks you though, im trying to get help from my host but its been a long wait and very little has been done.

I have recently changed server and setting things up are a right pain, after 2 days im need of some help. I have my site split into sub domains so lets say; www.domain.com one.domain.com two.domain.com three.domain.com They are to separate parts of my site which used to make it easier the manage each part, so one sub domain handles accounts and logins etc.. whilst another handles products and so on. the problem im having is all my login scripts and are on say 'one.domain.com', i can log in fine but when i visit any other domain im logged out, i can't seem to sort it out. i have tried setting my session cookie path and session cookie domain by painstakingly adding ini_set('session.save_path', '/var/www/vhosts/website.co.uk/httpdocs/tmp'); ini_set('session.cookie_domain', '.website.co.uk'); to every page, but it makes no difference, im also getting the occasional error Warning: session_start() [function.session-start]: open(/tmp/sess_d387ha6eqvj53f135q0fh4d733, O_RDWR) failed: Permission denied I have contacted my server provider by after endless messages they are no longer helping but rather keep saying 'leave it with us' then 'we fixed it' although they didnt. It doesn't help im so limited in what i have access to, i cant access the php.ini so everything has to be done via php So i would really appreciate any help getting this session problem sorted out. Thank you.

Hi, I have setup my paypal payment method for a shopping cart on my site, all is well but in order for my server to flag an invoice as paid, the user must return to my website after paying and the query string in the url give the script the go ahead to mark it as paid which in turn alerts the appropriate department that its ok to source the order. ~The problem is, if the user for whatever reason skip the redirect back to my site, the invoice is remain 'unpaid' and has to be changed manually when the payment has been checked in the account. As you might imagine this is a bit of a problem because not only can it cause quite a delay, it also requires manually changing values which can lead to other problems. So if there is a better way i would appreciate the info, thanks a lot.

Hi, im trying to work out a point based credit system on my site but require your expertise, The variable containing the total price of the invoice is called $TOTAL The amount of credit points a user has is saved as $credit My credit 'exchange' rate is 1000 credit points equal to £1 So my question is how do i go about subtracting the correct value from my total? I assume i have to divide the $credit variable by 1000 then do i simply just subtract this from the total? So something like // 1000 points £1 $credit_value = $credit / 1000; // set new total - credits $REDUCED_TOTAL = $TOTAL - $credit_value; or am i miles off? Thanks very much for any help, i urgently need to get this fixed.

I tried the function but i don't understand the out put, at 20:07 the output without using strtotime is 200700 (which i what i want), but when i use the function it makes it 1325448448

Yes i understand that, im forcing it as GMT at the moment, i will play about with it after i have the basics working. Thanks for the reply.

Im trying to get the current time, so lets says its 7 oclock, the value of time would then be (in 24hr, hour,min,sec) 190000 I then want to see what if this value is higher than day_start but lower than day_end, if not then it should be higher than night_start but lower than night_end. Why would this need a special function? Shouldn't it just be a standard check? Thank you for the help.

Hi, Im trying to create a simple script that will change the style sheet depending on the time of day. I have the following but it doesn't seem to be working. The stylesheets work fine when not used in the code (if i just add it to the head section) Appreciate any help <? // timezone date_default_timezone_set('GMT'); // check time $time = date("His"); // 6AM to 6PM $day_start = '060000'; $day_end = '180000'; // 6PM to 6AM $night_start = '180001'; $night_end = '055959'; // time of day if (($time >= $day_start) && ($time <= $day_end)) { // it is daytime // echo 'day'; echo '<link rel="stylesheet" media="screen" type="text/css" href="css/wc_parallax_day.css" />'; } if (($time >= $night_start) && ($time <= $night_end)) { // it is nighttime // echo 'night'; echo '<link rel="stylesheet" media="screen" type="text/css" href="css/wc_parallax_day.css" />'; } ?>

Hello, Im trying to create a simple voting script for my site, i been trying different things but cannot get it too function properly. The idea is you click the 'thumbs up' image to add 1 to the 'likes' value and thumbs down to add '1' to the dislikes. Sound simple but its giving me headaches. Would really appreciate it if someone could take a quick look at my script. The table is called 'youtube_rating' (because thats the look i was going for) and in the table is 4 columns, id (aut0_increment), liked (counts liked votes), disliked (counts dislikes) and item_num which is the id for teh product the rating is for. <? if ( $row['rating'] == 'YES' ) { require ("../rating/voting/dbcon.php"); $result1 = mysql_query("select * from youtube_rating WHERE item_num='".$page_id."'"); $row = mysql_fetch_array($result1); $dislike = $row['dislike']; $like = $row['liked']; if (isset($_POST['submitted'])) { require_once ("../database/functions.php"); $userip = $_SERVER['REMOTE_ADDR']; $id = safe($_POST['id']); $vote = '1'; // check if user already voted $result = mysql_query("SELECT * FROM youtube_ip WHERE userip='$userip' AND item_num ='".$id."'"); $num = mysql_num_rows($result); // if already voted show error if (isset($_POST['submitted']) && ($num > 0)) { echo '<div class="alreadyvoted">You have already voted!</div>'; } // add like if (isset($_POST['submitted']) && ($_POST['submitted'] == 'like') && ($num == 0)) { // add 1 to value $liked_value = mysql_query("SELECT liked FROM youtube_ip WHERE item_num ='".$id."'"); $liked_total = $liked_value + $vote; $query = "update youtube_rating set liked = '".$liked_total."' where item_num ='".$id."'"; echo '<div class="ilikethis">You like this!</div>'; } // add dislike if (isset($_POST['submitted']) && ($_POST['submitted'] == 'dislike') && ($num == 0)) { // add 1 to value $dislike_value = mysql_query("SELECT dislike FROM youtube_ip WHERE item_num ='".$id."'"); $dislike_total = $dislike_value + $vote; $query = "update youtube_rating set dislike = '".$dislike_total."' where item_num ='".$id."'"; echo '<div class="idislikethis">You Dislike this!</div>'; } // log ip // if (isset($_POST['submitted']) && ($num == 0)) // { // mysql_query ("insert into youtube_ip (userip, item_num) values ('".$userip."', '".$id."')"); // } } ?> <table width="50%" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td width="48%" align="center"> <form action="" method="post"> <input name="id" type="hidden" value="<? echo $page_id ?>" /> <input name="submitted" type="hidden" value="like" /> <button type="submit" class="like_button" name="like" id="like" > <img src="../rating/voting/pixel-vfl73.gif" alt=""> <span><?php echo $like?></span> </button> </form> </td> <td width="52%"> <form action="" method="post"> <input name="id" type="hidden" value="<? echo $page_id ?>" /> <input name="submitted" type="hidden" value="dislike" /> <button type="submit" class="dislike_button" name="dislike" id="dislike" > <img src="../rating/voting/pixel-vfl73.gif" alt=""> <span><? echo $dislike?></span> </button> </form> </td> </tr> </table> <? } ?> The problem is the vote does not add up or update the database, also it doesn't seem to be checking if the user has voted or not, it just attempts (but fails) to add a vote no matter what Thanks for any help.

Im trying to write a script so that upon clicking a link (which is a image in this case) it toggles a div displaying the necessary info below. the javascript <script type="text/javascript"> $(document).ready(function(){ $(".slidingDiv1").hide(); $(".show_hide1").show(); $('.show_hide1').click(function(){ $(".slidingDiv1").slideToggle(); }); }); </script> <script type="text/javascript"> $(document).ready(function(){ $(".slidingDiv2").hide(); $(".show_hide2").show(); $('.show_hide2').click(function(){ $(".slidingDiv2").slideToggle(); }); }); </script> snip from table <tr> <td class="style1"> News </td> <td><a href="#" class="show_hide1"><img src="/img/add-icon.gif" width="16" height="16" alt="" /></a></td> <td><a href="#" class="show_hide2"><img src="img/hr.gif" width="16" height="16" alt="" /></a></td> <td><img src="img/edit-icon.gif" width="16" height="16" alt="" /></td> <td><img src="img/login-icon.gif" width="16" height="16" alt="" /></td> <td><img src="img/save-icon.gif" width="16" height="16" alt="save" /></td> <td><img src="img/add-icon.gif" width="16" height="16" alt="add" /></td> </tr> the content that will be displayed upon pressing the link <div class="slidingDiv1"> <div id="admin_form"> <a href="#" class="show_hide1">Hide Form</a> form 1 test content </div> </div> Is it possible to hide all other divs when clicking a new link so only the relevant info is being shown? Also is there a way to cut this code down a bit rather than creating x amount of function that all do the exact same thing but just show different divs? Im going to have at least 20 in total so it seems a lot of wasted code if there is a way to cut it down.

Hi, Would someone please give me some assistance on how to display random products from my database I need to display a maximum of 6 images and there link in two rows of 3 so; [image] [image] [image] [image] [image] [image] and each image would have something like; <a href="<? echo $row['product_link'] ?>"><img src="<? echo $row['product_image'] ?>"/></a> but i don't know how to display these at random and make sure only 6 appear at a time. Thanks for any help, hope you understand what im trying to explain

Hi, sorry if this is the wrong place. I have made a new menu bar for my site on a separate php page, im loading this page in my template with require_once 'xxx.php'; The page loads but the css doesn't, i can't understand why because i have tried to include the css on the external page with <style> tags and i have also <link rel="stylesheet"..... either way it wont include the css for it.. any ideas? Thank you.

Can anyone see something wrong with this? It's driving me crazy and throwing up an error $sql_insert = ("INSERT INTO users ( 'user_name', 'user_email', 'user_credit', 'fname', 'lname', 'house_num', 'addr', 'addr2', 'county', 'postcode', 'pwd', 'dobDay', 'dobMonth', 'dobYear', 'tel', 'date', 'users_ip', 'avatar' ) VALUES ( '".$user_name."', '".$usr_email."', '0.00', '".$fname."', '".$lname."', '".$house_num."', '".$addr."', '".$addr2."', '".$county."', '".$postcode."', '".$sha1pass."', '".$dobDay."', '".$dobMonth."', '".$dobYear."', '".$tel."', '".$date."', '".$user_ip."', '/images/default/avatar.png' )"); echo $sql_insert; mysql_query($sql_insert,$link) or die(mysql_error()); I can't see what i wrong with it, i removed all the blank entries (ones with the value 'null',) but it didn't make any difference

That was really useful info, especially the script, so thank you very much. The only thing i need to know now is how to have the script continue to my processing page if there are no errors else { // Form was submitted, and validated with no errors. OK to run db insert, display success message, etc. echo "Successful submission!"; // continue to process page here?? } i tried to set the header but i cant because it was already sent

I have a form page (referred to as form.php) which is then processed via a submit button, the script then processes the data from the form.php and if it discovers an error it then sets a variable containing the error message my process page contains if (empty($b_addr)) { $b_addr_error = "Address is required"; $check_failed = TRUE;} header("Location: form.php"); then my form.php contains $b_addr_error = safe($_GET['b_addr_error']); if (isset($_POST['$b_addr_error'])) { echo "<div class='errorfont' align='center'>'".$b_addr_error."';</div>"; } but the variables do not get passed back to form.php from the process page, any ideas? Thank you.

Hi guys, im logging activity on my site to text files using; date_default_timezone_set('GMT'); $LogFileLocation = "xxxxxxxx.log"; $fh = fopen($_SERVER['DOCUMENT_ROOT'].$LogFileLocation,'at'); fwrite($fh,date('d.M.Y H:i:s')."\t".$_SERVER['REMOTE_ADDR']."\t".$_SERVER['REQUEST_URI']."\n"); fclose($fh); This is write something like; [date] [time] [ip address] [folder accessed] I then post it like; <? $fn = "xxxxxxxxxx.log"; print htmlspecialchars(implode("",file($fn))); ?> That works fine but what i want to be able to do is read/edit the text files, so the main things i need to add is; The ability to clear the log (using password for confirmation) not sure how to go about this because i don't know how to edit the text file <input name="password" type="text"> <input type="submit" value="Clear Log?"> I also need a script to read the log and alert me an ip address that isn't mine is found, maybe something like if (an ip that isn't mine == yes) echo "an unknown ip accessed something" Also lets say i have a script that checks if a name exists, how can i use a text file containing a list of names to be read by a script if (name exists in text file) echo "name exists" else echo "name doesn't exist" All these questions are similar in the fact i need to understand how to open and read text files for specific entries, hope you understand, thanks for any help.

That is exactly what i need mjdamato. Thank you very much for taking the time to write out the code, its very much appreciated. Works great!

Hi guys, i got the following code i wrote which displays a small pop up on screen if the user has mail, and display a little icon. The problem is it displays a new icon for each new mail message. How can i make it so it only display 1 icon no matter how many unread mail the user has. Or even better if not too complicated display a number next too the image? <? require'xxxxxxxxxxxxxxxxx.php'; mysql_select_db("membership") or die( "Unable to select database"); $sql=("SELECT * FROM user_alerts WHERE user_id = '".($_SESSION['user_id'])."'") or die (mysql_error()); if ($query=@mysql_query($sql)) { if (mysql_num_rows($query) > 0) { while ($req=mysql_fetch_array($query)) { if ($req['messageRead'] == 'NO') { ?> <div> <img src="xxxxxxxxxxxxxx.png" width="32" height="32" alt="unread mail" /> <a href="http://www.xxxxxxxxxxxx/account=account">You have Mail!</a> <div id="boxes"> <div style="top: 199.5px; left: 551.5px; display: none;" id="dialog" class="window"> <h2>You have new mail!</h2> <br /> <p>Visit your account page to read it.</p> <br> <a href="#" class="close">Close Window</a> </div> <!-- Mask to cover the whole screen --> <div style="width: 1478px; height: 602px; display: none; opacity: 0.8;" id="mask"></div> </div> </div> <? } } } } You can ignore most of the div stuff but that's pretty much it. It should check my database for any entries with the users session id in the column called 'user_id'. and only show the image if it then finds an entry with 'NO' in the 'messageRead' column. It currently shows the images for each entry it finds. Thanks for any help

Hi. I have a sort of security script which checks a few things, how can i save the url of the link that was clicked, so i can pass it through the script then if all is good, continue on to the url, if not send them somewhere else let me try to explain better with a little text picture user clicks link ----------------------> link goes to my security script --------------------> if the check passes, continue to original links url so basically i just need to know how to save the links url as a variable

Thank you for your example. The problem with that is the fields will contain different values. This script is too add special offers on my website, so for example i have 4 fields, discount percentage discount cash value set cash value shipping value So depending on the offer one of these fields will be filled out. Lets say i want to make a special offer on a item and make it cost £10. I would then type 10.00 in the box labelled 'set cash value' Now the variable for 'set cash value' would be set too '10.00' but i want to make sure the others are blank, if there not tell the user not too fill in more than one option.