[Help with Timthumb and custom thumbnails?]

Hello, I have a file upload site for my IRC channel, and I'm using timthumb to generate thumbnails.

 

The problem is, I allow users to upload other than image files and they obviously show as blank now on my website.

 

Any ideas how I could show custom made thumbnails for files such as .rar?

 

i.e. user uploads a rar file, and my site instead trying to do this:

<div class='tiedosto'><a href='up/rss.rar' class='tiedosto screenshot' rel='up/rss.rar' ><img src='thumb.php?src=up/rss.rar&h=100&w=100&zc=1' alt=''></a></div>

it would show this

<div class='tiedosto'><a href='up/rss.rar' class='tiedosto screenshot' rel='up/rss.rar' ><img src='thumb.php?src=thumb/rar.png&h=100&w=100&zc=1' alt=''></a></div>

or just

<div class='tiedosto'><a href='up/rss.rar' class='tiedosto screenshot' rel='up/rss.rar' ><img src='thumb/rar.png'></a></div>

 

Thanks.

[Problem with simple commenting script]

you can try ummm.... $_GET[id] on your send.php for your id and then on your blog.php's form do something like

<form action="send.php?id=<? echo "$_GET[id]"; ?>" method="post">

 

that way... it sends it to send.php with the id and you can use $_GET[id] once you are in send.php

Wow thanks, that did work after some tweaking!

 

$id = $_GET['id'];
mysql_query("INSERT INTO  Blog_kommentit (kayttajat ,  kommentti ,  kirjid)  VALUES ('$kayttajat',  '$kommentti',  '$id')") or die(mysql_error());

[Problem with simple commenting script]

Hello, I'm trying to create a simple php blog thing, and I can't get the commenting to work..

 

blog.php?id=2

 

On that page, there is a form what is used to comment, it goes to send.php

 

That php has this query in it:

 

$yhteys = mysql_connect('10.5.49.32', '09A_user', 'pass');
mysql_select_db('09A_Jere', $yhteys);
mysql_query("INSERT INTO  `Blog_kommentit` (`kayttajat` ,  `kommentti` ,  `kirjid` )  VALUES ('$kayttajat',  '$kommentti',  '$id')") or die(mysql_error())$sql = "SELECT * FROM Blog_kommentit WHERE kirjid='$id' ORDER BY id";;
mysql_close($yhteys);
header('Location: ' . $_SERVER['HTTP_REFERER']);

How can I make the $id to be previous pages id (2)? This shouldn't be anything hard and I'm kinda amazed why I am stuck in this, any help will be appreciated.

If I just put $id I get this error:

Cannot add or update a child row: a foreign key constraint fails (`09A_Jere/Blog_kommentit`, CONSTRAINT `kommentti_kirjoitus` FOREIGN KEY (`kirjid`) REFERENCES `Blog_kirjoitukset` (`id`))

Here is how my database works:

 

(Kayttajat = username, kommentti = comment)