yoda87
-
Posts
6 -
Joined
-
Last visited
Never
yoda87's Achievements
Newbie (1/5)
0
Reputation
-
Hello everyone, i have this page in my website called "index.php": <?php include("include/open_conn.php");?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>name site</title> </head> <body> <div id="container"> <?php include("include/header.php");?> <?php include("include/content.php");?> <?php include("include/footer.php");?> </div> </body> </html> <?php include("include/close_conn.php");?> The content change dinamically with this code "content.php": $pages_dir = 'pages'; if (!empty($_GET['menu'])) { $pages = scandir($pages_dir, 0); unset($pages[0], $pages[1]); $menu = $_GET['menu']; if (in_array($menu.'.php', $pages)) { include($pages_dir.'/'.$menu.'.php'); } So, when i change the page the url will be " index.php?menu=nameofmypage ". But now i want to put an image only in my index.php page, a sort of welcome to the users, but with this codes the image will appear in all the other page because i change only the content. I know that i could create a page named "home.php" and do all i want, but i want to change the first page that the user see when he types the address of my website. thank you!
-
Dreamweaver sign it as an error
-
Ok, here's my mistake, the original code i wrote was ... if (!is_dir($base."/".$get_album) || strstr($get_album,".") !=NULL || strstr($get_album,"/") !=NULL || strstr($get_album,"\\") !=NULL) { with two \\ , anyway there's other error, because don't work
-
here http://php.net/manual/en/function.strstr.php seems to be correct..
-
I see, but frist i use doble " and after single ', I do not know how to do otherwise...
-
Hi all, i've set this script for my gallery, it works, it display me the name of the albums, but when i click to see the pictures inside, the page is blank, and also don't appear the "Back to the albums" link, i can't find the error in the code... <html> <head> <script type="text/javascript" src="../lightbox2.05/js/lightbox.js"> </script> </head> <body> <?php $page = $_SERVER['PHP_SELF']; //settings $column = 5; //directories $base = "carrelli_noleggio"; $thumbs = "thumbs"; // get album $get_album = $_GET['album']; //if no album selected if (!$get_album) { echo "<b>Select an album:</b><p />"; //find each album and display as links $handle = opendir($base); while (($file = readdir($handle))!==FALSE) { if (is_dir($base."/".$file) && $file != "." && $file != ".." && $file != $thumbs) { echo "<a href='$page?album=$file'>$file</a><br />"; } } closedir($handle); } else { //check if album exist, and additional security checks if (!is_dir($base."/".$get_album) || strstr($get_album,".") !=NULL || strstr($get_album,"/") !=NULL || strstr($get_album,"\") !=NULL) { echo "Album doesn't exist."; } else { $x = 0; echo "<b>$get_album</b><p />"; $handle = opendir($base."/".$get_album); while (($file = readdir($handle)) !== FALSE) { if ($file != "." && $file != "..") { echo "<table style='display:inline;'><tr><td><a href='$base/$get_album/$files' ref='lightbox'<img src='$base/$thumbs/$file' height='100' width'100'></a></td></tr></table>"; $x++; if ($x==$column) { echo"<br />"; $x = 0; } } } closedir($handle); echo "<p /><a href='$page>Back to albums</a>"; } } ?> </body> </html>