theloveforphp

return does not produce output. It doesnt? Hmm, I must have missed something in my testing, it seems to work fine now. Thats odd because I tried the exact same thing yesterday and it echoed the formatted value. Anyhow, I'll mark this as solved and test it a bit further. Thanks to you both for the help!

Thats the thing, I dont want the function to echo the result as default. If I use "return" it will automatically echo the formatted value/variable and I want to be able to use it in a if-expression, which I cant if its echoing.

Hey! I have a small code where I want to check if one variable matches the other when the other is sent through a function. The function, for practical reasons, is included with a separate PHP-file. And I cant seem to apply a variable to the function which processes the other variable. Its really wierd to me. Here is the code for the main PHP-file: <?php include 'function.php'; $unformatted = "FORMATTING AY ..."; $formatted1 = "formattingay..."; $formatted2 = test_format($unformatted); if ($formatted1 == $formatted2) { echo "Success, formatted!"; } else { echo "Fail, unformatted."; } ?> And here is the code for "function.php": <?php function test_format($var) { strtolower(str_replace(array(" "), array(""), $var)); } ?> Does anybody have a clue to why this simply wont work? Any answers and help is highly appreciated!