[Newbie Help]

dude don't do the hard delete do soft delete example

put one more column in database say "status"

when user is created the status column for that user will be default active

and as soon as u try to delete the record don't delete the record just change the status to deactivated

and now when ever u try to display the list of user just display the list with active status

[Help with PHP menu]

i do know that but it would be great help i you can tell us the best and most suitable way to achieve the result

Rather than pointing the fingers on others

[Help with PHP menu]

<?php

$path = $_SERVER['SCRIPT_NAME'];

$script = explode("/", $path);

$filename = explode(".", $script[sizeof($script) - 1]);

?>

 

<li class="link">

<a class="link levela" title="The drive formally known as "P"">

<span>Company Documents</span></a>

<ul>

<li class="link">

<a class="<?php if ($filename[0] == "comm_forms") { echo "current"; }else{ echo "link"; } ?> levelb" href="http://hhnet/company_documents/comm_forms.php" title="Forms... for Commission">

<span>Commission Forms</span></a></li>

 

<li class="link">

<a class="<?php if ($filename[0] == "complaint_documentation") { echo "current"; }else{ echo "link"; } ?> levelb" href="http://hhnet/company_documents/complaint_documentation.php" title="Documents documenting complaints.">

<span>Complaint Documentation</span></a></li>

[Help with PHP menu]

put this code above ur php include file name menu.php

 

<?php

$path = $_SERVER['SCRIPT_NAME'];

$script = explode("/", $path);

$filename = explode(".", $script[sizeof($script) - 1]);

?>

[Syntax Error]

if($_SESSION['name']){

echo "<option value='".$_SESSION['name']."'>".$_SESSION['name']."</option>";

}

[login form - member and admin page after login]

wat u can do is

 

u should put one flag  column in database which will tell u whether the logged in user is admin or a normal client

Once u know which user has logged u u can redirect that user to the respective url

 

And yes it would be better to have different folder for different user type

 

say for admin it would be admin folder

and for user it would be user folder

[Having issues with displaying database query results]

according to me i think ur using same name for the variable or object for the queries please try to use different name for variable or query and than try it will get resolved

[date comparison]

$query = "SELECT * ";

$query .= "FROM table ";

$query .= "WHERE malls_id=" . $mall_id;

$query .=" AND DATE_FORMAT(date ,'%Y-%m' ) =" . $selected_date;

 

the above query has to be modified as below

 

$query = "SELECT * ";

$query .= "FROM table ";

$query .= "WHERE malls_id=" . $mall_id;

$query .=" AND YEAR(date) = '".$year."' AND MONTH(date) = '".$month."'";

 

 

[session_start() error]

one thing u can do just to hide that warning use

@session_start();

[First steps in JSON]

Hi dude still i m not completely cleared but

 

If you are getting value in an array format than u don't u store it in a variable and than use that variable to get that data example

$valueHolder = $json->call('getBits',Array());

 

print_r($valueHolder['success']);

[First steps in JSON]

hi herghost are u getting json result from ajax call from php page can u explain me bit about this i think i can help u out for the same

[Rename Images]

Can you try the code the way i have written don't change it place it has it is and try it out

 

function findexts ($filename) {

$filename = strtolower($filename) ;

$exts = split("[/\\.]", $filename) ;

$n = count($exts)-1; $exts = $exts[$n];

return $exts; }

 

 

$ext = findexts ($_FILES['foto']['name']) ; 

$ran2 = $foto."."; 

$target = "../images/";

 

$target = $target . $ran2.$ext;

while (file_exists($target)) {

    $ran2 = 'copyof'.$ran2;

    $target = $target . $ran2.$ext;

}

if(move_uploaded_file($_FILES['foto']['tmp_name'], $target))  {

$newFilename = $ran2 . "." . $ext;

mysql_query( "INSERT INTO `softmarket`.`internet_securitate` (`internet_securitateID`, `nume_produs`, `descriere`, `versiune`,`poza`, `pret`, `disponibilitate_produs`)

VALUES ('', '$_POST[titlu]', '$_POST[descriere]', '$_POST[versiune]', '$newFilename', '$_POST[pret]', '$_POST[disponibilitate]');");

echo "The file has been uploaded as ".$newFilename; }

 

else { echo "Sorry, there was a problem uploading your file."; }

 

 

 

header('Location: succes.php');

[Trying to restrict characters in regular expression to just a-z]

Try this below regex won't allow the numerice value

 

/^[a-zA-Z\s]+/

[Rename Images]

i got one can u just send me detail description abt ur problem

[Trying to restrict characters in regular expression to just a-z]

try this out

 

preg_match('/^[a-zA-Z\s]+/', 'this may or may not be valid with 1')

[PHP Classes & Data]

Can you try to clarify more about ur problem means are you telling that u have order form which user fills in and once it is fill u will create and array of all the data that user and filled in and will pass that array to the class function and insert it into the database than i say,

 

It is bad practice to create a array after the data is submitted since the u will get the data in post as an array format and again creating new array not good practice

[Rename Images]

If i m not mistaken i think the problem is that the name that u r storing in database is different and and file name is different because u r executing insert statement before the move_upload statement

 

Execute insert statement after the upload statement and instead of using $foto us $ran2

[How to do print job using php]

printer_open function which php use to support i don't have clear idea whether it is support in latest php version since i m using php 5.3.8

 

and also the php_printer extension is not present in my php version but i manually downloaded php_printer.dll from internet placed it in my php extension folder and i tried to enabled it but still no use

[Rename Images]

First can u tell us that wat is $foto variable holding i want to know what does it holds

 

 

And i you don't mind can i suggest u that why don't u change the name of the file on every upload means give new name to the file whenever user uploads a file use date function like this

 

$filename = date('dmYHis');

 

once u got he file name append the extension and store it in the folder, using this u will get a unique name for every upload that u do

[How to do print job using php]

Sorry for that but i m really frustrated as i m trying to print the document what i really want is that

 

First suppose their is a form with three input fileds

1. firstname

2. lastname

3. phone

as soon as user fills this details and press submit button the fill details should get insert into the database but at same time this fill details should get print

on a paper in format as below

Name of visitor : XYZ

Tell : 234567899

[How to do print job using php]

I have used php_printer.dll but it is of no used