[automatically moving to a div]

It is. After having a look at your code (which is not complete, so the solution will be a guess), I think you'll need to do following 2 steps

 

 

//1. add the named anchor above your div

<a name="line1"></a>
<div id="line1>hello</div>

 

//2. add following code just above the closing body tag ( </body> )
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST' && isset($submit_line))
{
?>
    <script type="text/javascript">window.location.hash = 'line1';</script>
<?php
}
?>

 

I hope this works.

[automatically moving to a div]

No that's not what I meant. It seems that you're not applying PRG (Post-Redirect-Get) pattern, if I understand correctly. Please post the form handling code.

[Really Simple Error - Help!]

you were misreading the array structure. The first line in var_dump output in reply # 3 is "array(1) {" which indicates that the outer array has only one element in it, so you can't do $matches[1]

 

Please mark solved if it is solved

 

[automatically moving to a div]

headers don't have to do anything with it. You will not be using the div's ID but a named anchor just above the target div instead. Say you want to "redirect (as you say)" the user to a specific div element with id=line1, you do something like this

 

//page test.php
//...
<a name="line1" />
<div id="line1>hello</div>

 

and then from the form submit handling script, redirect user to

test.php#line1

instead of just

test.php

 

The div's id is not bound to be same as named anchor's name.

[Cookies not being read until second load.]

If you are using 

header("Location: .....");

after

setCookie(...)

, cookie might not be set in all cases

[Trying to pass a variable from one file to another and cannot make it work]

This might work

 

--------------------------------------
ATSnotes.php

class ATSnotes extends ATSdb
//...

    function getNotes($stationID = 0)
    {
        $col = $this->getColumnNames();
        if (count($col) > 0)
        {
        //...
        $yada = $this->query("SELECT * FROM " . $this->getTableName() . ($stationID > 0? " WHERE fldStationID = $stationID " : '') . " ORDER BY $col[2] DESC, $col[2] DESC");
        //...

 

_________________________________________________ ____________________________________
3. stationNotesEditDel.php

//...
//...
unset ($dada);
$dada = $db->getNotes($StationID);
//...
//...

[Submit button working in Chrome but not in IE / MySQL Problem]

try adding

 

return true;

 

as the first line of

 

validateForm()

 

or just try removing

 

onsubmit = \"return validateForm()\"

 

from your string

 

[Really Simple Error - Help!]

you need to do

 

echo $match[0][1]; 

 

instead of

 

echo $match[1]; 

[$_SERVER['DOCUMENT_ROOT'] as path to root?]

@.josh +1

[$_SERVER['DOCUMENT_ROOT'] as path to root?]

you may need to do

 

<?php
$protocol = (!empty($_SERVER['HTTPS']) && $_SERVER['HTTPS'] !== 'off' || $_SERVER['SERVER_PORT'] == 443) ? "https://" : "http://";
$domain_name = $_SERVER['HTTP_HOST'];
$site_url = $protocol.$domain_name;
?>

<link rel="stylesheet" href="<?php echo $site_url ?>/css/style.css">

[Grouping sql results]

//code to divide array into chunks of size 10
$group_size = 10;
$input_array = array_chunk($input_array, $group_size, true)

[Table Inside Form ID Variable]

Pls post your table HTML (not php code that generates the table) and the PHP code that does database update.

[Warning: mysql_num_rows() expects parameter 1 to be resource]

it happens sometimes

[Warning: mysql_num_rows() expects parameter 1 to be resource]

replace

 

if(mysql_num_rows($blog_sql==0)){

 

with

 

if(mysql_num_rows($blog_sql)==0){

[PHP Help!]

<?php

if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
    if (isset($_POST["pokemon_id"]))
    {
        $result = mysql_query("SELECT * FROM firemap WHERE id = " . intval($_POST["pokemon_id"]));

        $row = mysql_fetch_assoc($result); // or whatever you do with plain mysql functions

        if (isset($row['id']))
        {
            echo "<div class=\"pokemonalign\">";
            echo $row['image'];
            echo "</br>";
            echo 'You have captured Wild';
            echo $row['name'] . "";
            echo "</div>";
            $add = mysql_query("INSERT INTO pokemon (pokedex_id, owner_id, type, nickname) VALUES ('$row[id]', '$id', '1', '$row[name]')");
        }
    }
}
else
{
    $map = rand(1, 10);
    $result = mysql_query("SELECT * FROM firemap ORDER BY RAND() LIMIT 1");
    while ($row = mysql_fetch_array($result))
    {
        if ($map == 1)
        {
            echo "<br />";
            echo '<img src="' . $row['image'] . '" alt="" />';
            echo "<br />";
            echo "A wild ";
            echo $row['name'] . " Appeared. <br /> Level: " . $row['level'];
            echo "<br />";
            echo "<form action='map1.php' method='post'>";
            echo "<input type='hidden' name='pokemon_id' value='$row[id]' />";
            echo "<input type='submit' class='catchpokemon' value='Catch $row[name]' />";
            echo "</form>";
        }
        else
        {
            echo "<div class=\"pokemontext\">";
            echo "<b>No more wild Pokémon appeared.</b>";
            echo "<br />";
            echo "<i>Keep moving around to find one.</i>";
            echo "</div>";
        }
    }
}
?>

[PHP Help!]

Following jesirose's suggestion, here's what you want (I'm bored to hell)

 

<?php

if (isset($_POST["pokemon_id"]))
{
    $result = mysql_query("SELECT * FROM firemap WHERE id = " . intval($_POST["pokemon_id"]));

    $row = mysql_fetch_assoc($result); // or whatever you do with plain mysql functions

    if (isset($row['id']))
    {
        echo "<div class=\"pokemonalign\">";
        echo $row['image'];
        echo "</br>";
        echo 'You have captured Wild';
        echo $row['name'] . "";
        echo "</div>";
        $add = mysql_query("INSERT INTO pokemon (pokedex_id, owner_id, type, nickname) VALUES ('$row[id]', '$id', '1', '$row[name]')");
    }
}


$map = rand(1, 10);
$result = mysql_query("SELECT * FROM firemap ORDER BY RAND() LIMIT 1");
while ($row = mysql_fetch_array($result))
{
    if ($map == 1)
    {
        echo "<br />";
        echo '<img src="' . $row['image'] . '" alt="" />';
        echo "<br />";
        echo "A wild ";
        echo $row['name'] . " Appeared. <br /> Level: " . $row['level'];
        echo "<br />";
        echo "<form action='map1.php' method='post'>";
        echo "<input type='hidden' name='pokemon_id' value='$row[id]' />";
        echo "<input type='submit' class='catchpokemon' value='Catch $row[name]' />";
        echo "</form>";
    }
    else
    {
        echo "<div class=\"pokemontext\">";
        echo "<b>No more wild Pokémon appeared.</b>";
        echo "<br />";
        echo "<i>Keep moving around to find one.</i>";
        echo "</div>";
    }
}
?>

[Strange file access issue]

Ok I got it resolved. It had nothing to do with ffmpeg.

Originally the "$thumb" and "$source" strings were different than my original post. The string were in following form (notice the quotes)

//original dev's code format
$source = '"/home/test1/abc.mov"';
$thumb = '"/home/test1/thumb.jpg"';

Something on the server got updated (by admins) and the code stopped working :|

 

I hope it helps somebody somehow.

thanks.

[PHP Help!]

I have been under the impression that it's the other way around

[Strange file access issue]

thanks for the quick reply.

here's the code (I'm debugging atm)

 

if (file_exists($thumb))
{
    echo "<pre>thumb exists</pre>";
}
else
{
    echo "<pre>thumb can not be accessed</pre>";
}

 

and I always get "thumb can not be accessed"

[PHP Help!]

I think you want

if(isset($_POST["$row[name]"])) 

instead of

if(isset($_POST['$row[name]'])) 

if this forum is not replacing your quotes.

[Strange file access issue]

Hello,

I'm having a very strange issue which i'm unable to identify/resolve.

 

I'm extracting an image using ffmpeg using following command

$source = '/home/test1/abc.mov';
$thumb = '/home/test1/thumb.jpg';
system('ffmpeg -i "' . $source . '" -ss 6 -vcodec mjpeg -f image2 -s 180x100 ' . $thumb);

This piece of code works fine and I can see the file, thumb.jpg, in the FTP fine. But if I run a

file_exists($thumb);

right after the above piece of code, PHP can't find the file. The image is created as is a valid jpg file (displays fine if downloaded via FTP)

I'm able to access all other files in '/home/test1/' directory using file_get_contents(); and file_exists() without any issues.

Any help would be appreciated.

thanks