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About bleured27
- Birthday 11/24/1996
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hy there please put your code between code tags, beside that did you test if your host apche is on/supporting
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oh well they do that whith an variation of id becose id never is the save you can't get the same picture. (don't you know id?=>learn mysql or an other databese that connects whith php)
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you could make random numbers whith pi and time to get pi as exactly as possible use this calculation . <table><tr><?php $c='3';$d=1;$md=1000000; $s=3; $pi =10000000000000; $pi2=10000000000000; while($d<=$md){ if($s==4) { $pi=$pi+($pi2/$c); $s=3; $pi3=$pi*4; $result = mb_substr($pi3, 0, 1); $result2 = mb_substr($pi3, 1, 300); echo"<td>line".$d."</td><td>:</td><td>";echo $result.".".$result2."</td></tr><tr>"; } else{ $pi=$pi-($pi2/$c); $s=4; $pi3=$pi*4; $result = mb_substr($pi3, 0, 1); $result2 = mb_substr($pi3, 1, 300); echo"<td>line".$d."</td><td>:</td><td>";echo $result.".".$result2."</td></tr><tr>"; } $c=$c+2; $d=$d+1; } $pi=$pi*4; echo $pi; ?> </table> (php might not be the best script to do this) and use a calculation whith pi to take a digit (i always use this way to get random numbers.) <?php $result = mb_substr($pi, 1, 3); //this takes the 2,3,4 character of the variable $pi $result = mb_substr($pi, 1, 2); //this takes the 2,3 character of the variable $pi //so mb_substr($pi[difines the variable's characters you take] //mb_substr($pi, 1[difines the characters you skip,change it to a calculation of time for random] //mb_substr($pi, 1, 2[this difines how long your new variable is]); //so $number ="390534"; $result = mb_substr($number, 1, 4);//this makes 9053 //so result="9053"; ?> to find pi better in php(les likly to crash your server/browser) (origanily mad for testing php's calculating skills this didn't work 100% properly becose if you put in a to high number(in the code not in the form) you get the hexidemential (or something like that) numbers) <form action="" method="post"> <input type="text" name="md"> <input type="submit" value="calculate"> </form> <?php if(isset($_POST['md'])){ ?> <table><tr><?php $c='3';$d=1;$md=$_POST['md']; $s=3; $pi =10000000000000; $pi2=10000000000000; while($d<=$md){ if($s==4) { $pi=$pi+($pi2/$c); $s=3; $pi3=$pi*4; $result = mb_substr($pi3, 0, 1); $result2 = mb_substr($pi3, 1, 300); echo"<td>line".$d."</td><td>:</td><td>";echo $result.".".$result2."</td></tr><tr>"; } else{ $pi=$pi-($pi2/$c); $s=4; $pi3=$pi*4; $result = mb_substr($pi3, 0, 1); $result2 = mb_substr($pi3, 1, 300); echo"<td>line".$d."</td><td>:</td><td>";echo $result.".".$result2."</td></tr><tr>"; } $c=$c+2; $d=$d+1; } $pi=$pi*4; $result = mb_substr($pi3, 0, 1); $result2 = mb_substr($pi3, 1, 300); echo"best result =".$result.".".$result2; ?> </table> <?php }else{echo"see how many pi multiplayers your pc can handle<br /> pi=4*(1-1/3[multiplayer1]+1/5[multiplayer2] etcetra)";}?>
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Refresh a particular div section after mouse release
bleured27 replied to NaniG's topic in Javascript Help
do you use dynamic code in the div? -
please put your codes between code taggs so it's easy reading.
- 1 reply
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- javascript
- onload
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(and 1 more)
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<a href="showBadges1.php" class="nyroModal" style="display:none"></a> <a href="showBadges2.php" class="nyroModal" style="display:none"></a> <a href="showBadges3.php" class="nyroModal" style="display:none"></a> <script> $(document).ready(function() { //how can I run associate above links to nyromodal one by one. That is next popup appears only if previous get disappeared. $('a.nyroModal').each(function(){ $(this).nyroModal({ minWidth:500,minHeight:580, modal:true}); $(this).trigger('click'); }); )} </script> you should create a diffrend function for popup and change the class of each picture, becose it all have the same class the script activate all pictures to popup
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hy i am looking for a list with all javascript codes and pre defined variables. why? because i understand the basics of javascript how it works and how to applay almost evrything,still i keep forgetting the codes, so i have to find them again. so i would like to have a list so i can learn easy all the codes do you have one? because i really would appriciate if you can give me one btw ) sorry for my worse Englisch just a joung programmer here.
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Parse error: syntax error, unexpected 'or' (T_LOGICAL_OR)
bleured27 replied to bleured27's topic in PHP Coding Help
salathe im just 16 years old and programming for 4 years you can't expect me to know evry liddle thing the most people learn while they r studying -
Parse error: syntax error, unexpected 'or' (T_LOGICAL_OR)
bleured27 replied to bleured27's topic in PHP Coding Help
ow jhea thank you jazz i didn't knew it was pre determent in mysql when i did that it worked fine it only is still a bid starnge that it gives an OR error and you jessica tnx for being so enoying it helped me not at all why do you even post here when you have nothing to bring in>?? btw do you know the meaning of newb. Lulz -
Parse error: syntax error, unexpected 'or' (T_LOGICAL_OR)
bleured27 replied to bleured27's topic in PHP Coding Help
!btw i know what it does i just include this in to my whole code when im finisched! -
Parse error: syntax error, unexpected 'or' (T_LOGICAL_OR)
bleured27 replied to bleured27's topic in PHP Coding Help
i was just eating but this is the entire code CTRL + Q to Enable/Disable GoPhoto.it i was just eating and i will ignore your nonsens stilll this is the entire code . for you to post again <?php require('connection.php'); $user=1; $result = mysql_query("SELECT * FROM $table_messages where reciver='$user'", $con); $num_rows = mysql_num_rows($result); if($num_rows ="0" ){echo " no messages";}else{ echo $num_rows." messages";} ?> <?php $con = mysql_connect("localhost","sh","onyou"); mysql_select_db("game", $con); $table="accaunts"; $table_kingdom="members"; $table_messages="messages"; ?> if you can't solve this problem il go read some more books and hey don't be to hard for me im just an starting programmer who isn't even an adult so keep your smartass notices in front of you -
Parse error: syntax error, unexpected 'or' (T_LOGICAL_OR)
bleured27 replied to bleured27's topic in PHP Coding Help
how every when i put (mysql_error()); on again the same error comes -
Parse error: syntax error, unexpected 'or' (T_LOGICAL_OR)
bleured27 replied to bleured27's topic in PHP Coding Help
hy i found something it is working whith other variables or get away a bit it works when i do $result = mysql_query("SELECT * FROM $table_messages where reciver='$user'", $con); //i rechecked the variables in my db and they are right i don't understand why this cant the error must be in '$user' and read !='1'", $con);or die(mysql_error()); -
Parse error: syntax error, unexpected 'or' (T_LOGICAL_OR)
bleured27 replied to bleured27's topic in PHP Coding Help
same error whith this <?php require('connection.php'); $user=1; $result = mysql_query("SELECT * FROM $table_messages where reciver='$user' and read !='1'", $con);or die(mysql_error()); $num_rows = mysql_num_rows($result); if($num_rows ="0" ){echo " no messages";}else{ echo $num_rows." messages";} ?> -
Parse error: syntax error, unexpected 'or' (T_LOGICAL_OR)
bleured27 replied to bleured27's topic in PHP Coding Help
no that was where i stucked to i dont have anything like OR those are the full documents u see there