[PHP functions in PHP arrays]

Hi,

 

I have this array which contaisn a php function. When I call upon the array value I would like to use the function (The array value) as normal php.

 

Array
(
   [item1] => $GLOBALS["class"]->function(1),
[item2] => $GLOBALS["class"]->function(4)
)

[Move arrays up]

Problem with using is the array is built like this:

 

function files(){
$file_array = $this->files;
$files = array();
foreach($file_array as $value){
$files[] = $value['files'];
}
return $files;
}

 

That funcxtion is from a class file. That functiopn returns the array posted above. How can I make all the valueas into one array mate?

[Move arrays up]

Hey,

 

Could someone help me move these arrays into one array please? i.e move them up one level.

 

Array
(
   [0] => Array
    (
	    [0] => content_first
    )
   [1] => Array
    (
	    [0] => content_again
	    [1] => content
    )
}

 

Thanks.

[Php Logs In With Incorrect User/pass]

I know all this. I used a switch because I normnally use a switch to do a password forgotten case and register.

 

Here is a quick secure class I wrote which you can use to secure your password:

 

<?php
class secure{

## GET A RANDOM SALT
function secure_random_salt(){
$randtext = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890';

$varlen = rand(5, 20);
$randtextlen = strlen($randtext);
$salt = '';

for($i = 0; $i < $varlen; $i++){

$salt .= substr($randtext,rand(1,$randtextlen),1);
}

return $salt;
}


## ENCODES PASSWORD
function secure_encode_password($password, $salt = ''){
if($salt == ''){

$salt = $this->secure_random_salt();
}

 return md5($password.$salt).':'.$salt;
}


## CHECK PASSWORDS MATCHES
function secure_check_password($password, $db_password){

$explode = explode(':', $db_password);
if(isset($explode[1])){

if($this->secure_encode_password($password, $explode[1]) == $db_password){

return true;
}else{

return false;
}
}else{

return false;
}
}
}
$secure = new secure;
?>

 

Simply including the class file and do this to create your password string.

 

// There is more to this class but I have cut it down. You could create a new function which will secure the posted values like the guys mention above.

$insert_password = $secure->secure_encode_password($password); // Password to insert into the db.

// And to check if the password is the same when they post it:


// $db_password is the actual password from the database.
// $password is the password posted from the login form.

if($secure->secure_check_password($password, $db_password)){
// Log the user in. $_SESSION etc..
}

[Software Semantic Versioning]

But doing a software update this way is the very best way to do it?

[Software Semantic Versioning]

Christian, Thanks man. I never knew you could do it like that with a switch statement. I always thought it read everything at once doing switches like that. Thats awesome. Thanks

[Software Semantic Versioning]

Say for instance. I release version 3.0.4 But the user is still on version 1.0.2. It needs to update them all in order.

[Software Semantic Versioning]

Can you do me a little sample? I am kind of lost at what you mean mate. Thanks

[Php Logs In With Incorrect User/pass]

Hey,

 

I have written you something that you could incorporate into your script. I basically wrote this with my eyes closed and I haven't tested it. If you get issues let me know and I can help.

 

You need to add a hidden input into your login form and call it: login & give it a value of 1.

You would also need to implement your password encoding where it says: Do your password encoding.

 

<?php

$case = isset($_POST['login']) ? 'login' : false;
$error = false;
switch($case){

case'login':

 $username = isset($_POST['username']) ? mysqli_real_escape_string($mysqli, $_POST['username']) : false;
 $password = isset($_POST['password']) ? mysqli_real_escape_string($mysqli, $_POST['password']) : false;

 if($username && $password){

  // Do your password encoding here. $password = ?

  $query = mysqli_query($mysqli, "SELECT * FROM Persons WHERE Username = '$username' AND password = '$password'");
  $numrows = mysqli_num_rows($query);

  if($numrows > 0){

   $row = mysqli_fetch_assoc($query);

   // Set sessions
   $_SESSION['login'] = true;
   $_SESSION['ID'] = $row['PlayerID'];
   $_SESSION['username'] = $row['Username'];
   $_SESSION['email'] = $row['Email'];

   // Redirect
   header("Location: loggedin.php");

  }else{

   $error = true;
  }
 }else{

  $error = true;
 }
break;
}
if($error){

echo '<font color=red>Authentication failed</font>';
}
echo 'Display login form here';
?>

[Software Semantic Versioning]

Hey guys,

 

I registered on another forum hot.... they never activated my account or help me so here it goes. I hope you guys are friendly

 

I am basically trying to return an array with all the versions that the current software hasn't updated too. (I am making a software update script)

I have built everything else including an API etc.. I have 12 years php knowlegde but this is bugging me and I have never come across this before.

 

So I have an array:

 

private $current_versions = array(

'1.0.0',
'1.0.1',
'1.0.2',
'1.1.0',
'1.1.1',
'1.1.2'

);

 

This array is all of the versions for the software.

 

I have two other variables:

 

$current_version = '1.0.2';
$new_version = '1.1.2';

 

I am basically trying to get the difference. The current version the software is running is: 1.0.2 and the current actual version of the software is: 1.1.2. I need to return an array with just the versions the software is missing, so that I can run the update based on them versions only; in order.

 

Thanks for your help and I will be taking part in this forum full time