benjahnee

when there is a user logged in they should be directed to members.php but even when logged in i get redirected to login.php instead of members.php, how do i fix this? im new aswell so try and make it simple for me <?php require('connect.php'); $sesuser = @$_SESSION['username']; $username = @$_POST['username']; $password = @$_POST['password']; $submit = @$_POST['submit']; if ($sesuser) { header( 'Location: members.php' ) ; } else { header( 'Location: login.php' ) ; } ?>

thanks alot il give it a shot

thats fine about email sorry i wasnt very clear.. i need it to sumhow display what actual numbers have been guessed, as well as how many guesses have been made?

oh one more thing paul ryan could you show me what code to add so that it displays what numbers have been guessed please thanks a bunch

paul ryan u sir are my hero are u open to giving me ur email so i could discuss problems i may have with u in the future? i wont pester you all the time i promise

ok i have tried some code but i have an error on the first line. could someone please tell me how to fix it. the error is Parse error: syntax error, unexpected '=', expecting ',' or ')' in F:\EasyPHP-12.1\www\scripting\guessinggame.php on line 1 and my code is <?phpif(isset($_POST['guess'])){if(!isset($_SESSION['life']=1);else if($_SESSION['life']==7){echo "Your Life end<br>Thanks for playing<br>";unset($_SESSION['life']);}else$_SESSION['life']++;$guess=intval($_POST['guess']);$secret=rand(1,10);if($guess==$secret){$output="<h1>Correct!</h1>";$output .="<a href='guessinggame.php'>Play again</a>";unset($_SESSION['life']);}elseif($guess<$secret){$output.="<h1>Your answer was too low. Please try again!";}else{$output.="<h2>Your answer was too high. Please try again!</h2>";}}?> [code/] any ideas???

hello guys i have some guessing game code that works fine i just need a few things adding to it that i dont know how to do if some body could please show me how. its just a simple number game where the user has to keep guessing numbers between 1 and 10 till they get it right. could somebody please how me how to add to the code so that. - there is a counter that tells the user how many guesses they have had. - the program stops at 7 guesses. thanks guys my code is if(isset($_POST['guess'])) { $guess = intval($_POST['guess']); $secret = intval($_POST['secret']); $output = ""; if($guess == $secret) { $output .= "<h1>Correct!</h1>"; $output .= "<a href='guessinggame.php'>Play again</a>"; } elseif($guess < $secret) { $output .= "<h1>Your answer was too low. Please try again!"; } else { $output .= "<h2>Your answer was too high. Please try again!</h2>"; } } ?>

hi guys i have created my first login and registration page but it does not work correctly. After submitting registration deals, the details are accepted and the user gets taken to a page that just says registration succesful. but when i run the logout script and try to log in using the details it says user details not recognised. so when i look in the database connected to the registration details, i found out that the registration details havent saved there. could someone please look at my code and tell me why these details arent being saved in the database? i appreciate it a lot thankyou the code is here http://pastebin.com/sSf3LnCu

hello guys im kind of new to this so please be nice. i am looking for advice more on the hprocess of how to do something rather than the exact code. maybe somebody could give me a short guide or step to step process idea. my task is to have an events page on a website i am making for an assignment. the events page must display the 5 nearest upcoming events the user must also be able to rearrange the events by distance or type of even. the events will be stored in a database. could somebody please offer me some advice on the best process to follow to do this task. thanks a bunch

thanks for the advice guys very helpful all is now sorted

Notice: Undefined variable: _SESSION in F:\EasyPHP-12.1\www\scripting\inc\header.php on line 42 i dont understand why i get this??

hi guys i haver a problem with my code it works but also shows an error when i run it the line of code where there is an error is this <code> <?php echo ($_SESSION['switchcss'])? $_SESSION['switchcss']: '<link href="css/alternate.css" type="text/css" rel="stylesheet">';?> <code> its for a php based css style switcher. if u need to know all of the code i am using to diagnose the problem i will leave it below, thanks alot guys <code> <?php include ("inc/css.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <div id="header"> </div> <?php if(isset($_GET['css'])){ switch ($_GET['css']) { case 'main': $stylesheet = '<link rel="stylesheet" type="text/css" href="css/main.css">'; $_SESSION['switchcss']=$stylesheet; break; case 'alternate2': $stylesheet = '<link rel="stylesheet" type="text/css" href="css/alternate2.css">'; $_SESSION['switchcss']=$stylesheet; break; case 'alternate3': $stylesheet = '<link rel="stylesheet" type="text/css" href="css/alternate3.css">'; $_SESSION['switchcss']=$stylesheet; break; // Our default stylesheet default: $stylesheet = '<link rel="stylesheet" type="text/css" href="css/alternate.css">'; $_SESSION['switchcss']=$stylesheet; } } ?> <?php echo ($_SESSION['switchcss'])? $_SESSION['switchcss']: '<link href="css/alternate.css" type="text/css" rel="stylesheet">';?> <a href="index1.php?css=main">[style 1]</a> |<a href="index1.php?css=alternate">[style 2]</a> | <a href="index1.php?css=alternate2">[style 3]</a> <a href="index1.php?css=alternate3">[style 4]</a> <code>

i called both the table and the database "products" would this cause a problem?

hello guys i have made a basic database in myadmin and i have written php code to connect to it. my database is called products. When i run the page i get the output - Connection Successful could not connect to products can somebody look at my code and tell me why i can not connect to my database <?php $host="localhost"; $user=""; $password=""; $db = "products"; $connect = mysql_connect($host, $user, $password); if($connect) { echo "Connection Successful"; $select = mysql_select_db($db); if ($select) { echo "<br /> connected to ".$db; } else { echo "<be /> could not connect to ".$db; } } else { echo "failed connection"; } ?> thankyou

Thanks alot love2code that is much better for me. Woud your be able to expand a little further for me though please. I would like it if when the guess was correct, the guess box is omitted and just the message and option to play again is displayed. i cant figure out how to do it. thanks