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Birdzview

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Posts posted by Birdzview

  1. Yes, that's exactly the problem - but how shall I fix it ?

    Please look at the code of CREATEMOVIE.PHP that generated the table - does the problem lie here ?

    Or does the problem lie with the data itself that I want to upload from MOVIEDATA.PHP ?

    Where do I find the table that was generated to see the data in it ?

  2. Please help, anybody

    Duplicate entry '1' for key 'PRIMARY' - The message I get when running my moviedata.php See also moviecreate.php that creates the database
    Here are the parts involved :

    A) MOVIEDATA.PHP (THE PROBLEM ONE)

     

    <?php
    //insert data into "movie" table
    $insert = "INSERT INTO movie(movie_id, movie_name, movie_type, " .
    "movie_year, movie_leadactor, movie_director) " .
    "VALUES(1, 'Bruce Almighty', 5, 2003, 1, 2), " .
    "(2, 'Office Space', 5, 1999, 5, 6), " .
    "(3, 'Grand Canyon', 2, 1991, 4, 3)";
    $results = mysql_query($insert)
    or die(mysql_error());
    ?>
     

     



    B) CREATEMOVIE.PHP (WORKS JUST FINE)

     

    <?php
    
    //connect to MySQL
    $connect = mysql_connect("localhost", "root", "") or
    die ("Hey boy, check your server connection.");
    
    //create the main database if it doesn't already exist
    $create = mysql_query("CREATE DATABASE IF NOT EXISTS moviesite")
    or die(mysql_error());
    
    //make sure our recently created database is the active one
    mysql_select_db("moviesite");
    
    //create "movie" table
    $movie = "CREATE TABLE movie (
    movie_id int(11) NOT NULL auto_increment,
    movie_name varchar(255) NOT NULL,
    movie_type tinyint(2) NOT NULL default 0,
    movie_year int(4) NOT NULL default 0,
    movie_leadactor int(11) NOT NULL default 0,
    movie_director int(11) NOT NULL default 0,
    PRIMARY KEY (movie_id),
    KEY movie_type (movie_type, movie_year)
    )";
    
    $results = mysql_query($movie)
    or die (mysql_error());
    ?>
     
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