h0m3r0w
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Posts posted by h0m3r0w
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I think you have an error in your query. Try using mysqli_error() to find out what it is:
$q = "select lastName, firstName, jobTitle from Employees where OfficeCode='$code'" if (!($result = mysqli_query($dbc, $q))) error_log(mysqli_error($dbc)."<br/>\nQuery: ".$q);
Here, I noticed that I'm a complete idiot. I forgot to select a specific database... When I connect to mySQL, I have a list of databases. While the one I hidden was indeed a database, it wasn't the correct one... So, now that I have that done, I'm still getting the exact same error for some reason...
I think I see the problem or part of the problem. It is telling you that the first parameter of your mysqli_query argument is incorrect, so the $dbc is not working. Look at this...
DEFINE ('DB_USER', '*******); DEFINE ('DB_PASSWORD', '******'); DEFINE ('DB_HOST','*****'); DEFINE ('DB_NAME','******');Your DEFINE DB_USER is missing a ' at the end of the ********.
See if that works!
Haha, sorry but that was a typo on my part. There actually was another single quote, I just made an error while trying to conceal some of the information. I'm no good at PHP, so I'm unsure as to how much code I should be revealing, since I'm connecting to my network and all that.
But all in all, I made a dumb error in connecting to the wrong database. But even with the correct database selected, I get an error. Well, I BELIEVE that I'm connected to the database. Do I need to use a "use ********" statement in the php? Where the **** is the name of one of the databases ("classicmodels") that I need to connect to?
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Hello all,
I'm having a bit of a problem with my code here.
I'm trying to allow the user to enter a number (an office number) from a database, and based on that value, after submitting it, an html table will fill with the appropriate results (lastName, firstName, jobTitle). For whatever reason, though, I keep getting this error:
"Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in... <website name> <line number>"
It's very weird, because I'm doing this straight from notes / w3 and I'm still getting errors. I'm still new to this, so I'm sorry if I'm sounding completely inexperienced... well I am haha.
Anyway, here's the code:
<!DOCTYPE html > <html lang ="en"> <head> <title> Homepage </title> </head> <body bgcolor="gray"> <h1 align=middle> Welcome to the Site </h1> <?php DEFINE ('DB_USER', '*******); DEFINE ('DB_PASSWORD', '******'); DEFINE ('DB_HOST','*****'); DEFINE ('DB_NAME','******'); $dbc = @mysqli_connect(DB_HOST,DB_USER,DB_PASSWORD,DB_NAME) or die ('Could not connect to MySQL: '.mysqli_connect_error($dbc) ); mysqli_set_charset($dbc, 'utf8'); //$r = @mysqli_query($dbc, $q); ?> <form action ="Homepage.php" method="get"> Enter Office Code: <input type="text" name="oCode" id="OfficeCode" maxlength="15"> <input type="submit" name="formSubmit" value="Submit"> </form> <? $code = $_GET['oCode']; $result = mysqli_query($dbc, "select lastName, firstName, jobTitle from Employees where OfficeCode='$code'"); echo "<table border='1'>"; echo "<tr>"; echo "<th>LastName</th>"; echo "<th>FirstName</th>"; echo "<th>Job Title</th>"; echo "</tr>"; while ($row = mysqli_fetch_array($result)) //this is where I'm getting the error { echo "<tr>"; echo "<td>" . $row['lastName'] . "</td>"; echo "<td>" . $row['firstName']. "</td>"; echo "<td>" . $row['jobTitle'] . "</td>"; echo "</tr>"; } echo "</table>"; mysqli_close($dbc); ?>Any help would be great. Thank you!
Filling PHP Table
in PHP Coding Help
Posted
Well, on that note, I have gotten everything completed. Thank you guys so much for the help. So, at the end of the day, it was me inserting the incorrect database... Thanks again guys!