[Checkbox & If..Else statement]

Sorry, I'm new to forum. ><

there are 3 checkbox actually, i would like to display different result when different checkbox are selected.

the value of checkbox is get from the previous page.

 

the rule is:

IF checkbox=1 THEN result=1

IF checkbox=2 THEN result=2

IF checkbox=3 THEN result=3

IF checkbox=1 AND checkbox=2 THEN result=4

IF checkbox=1 AND checkbox=3 THEN result=5

 

IF checkbox=2 AND checkbox=3 THEN result=6

IF checkbox=1 AND checkbox=2 AND checkbox=3 THEN result=7

 

how will the code look like when i want a combination ? im keep trying but i can't solve it.

Can you please teach me? thank you

[Checkbox & If..Else statement]

Can anybody help me to check what's wrong with the coding.
First, i get the value of checkbox from the previous page.
So, if checkbox 1 and 2 is selected, result with result_id 4 will be shown.
if checkbox 1 and 3 is selected, result with result_id 5 will be shown.

Now the problem is...no matter which checkbox is selected, the program will only run 'if statement' ,
which is result_id 4.
Below is the coding.
Hope you guys can help me. >< .Thank alot!!

<?php
session_start();
if(isset($_GET['checkbox'])){
$checkbox = $_GET['checkbox'];
}

else {
header('Location:tutorial.php');
}

include("database.php");

for($i=0; $i < count($checkbox); $i++){
{
if ($checkbox[$i]= '1' && $checkbox[$i]= '2'){
$sql="SELECT * FROM result WHERE result.result_id = 4";}

elseif ($checkbox[$i]='1' && $checkbox[$i]= '3'){
$sql="SELECT * FROM result WHERE result.result_id = 5";}

else {}

}
}

$result=mysql_query($sql); 

echo "<form action = 'result.php' method='POST'> 
<br/>";
echo "<table>";
while($row = mysql_fetch_array($result))
{
$result_name=$row['result_name'];
$result_id=$row['result_id'];
$result_desc=$row['result_desc'];
$image=$row['image'];

echo "<h4>$result_name</h4> ";

echo "<tr >";
echo "<td>";
echo "</form>";?>
<img src="<?php echo $row ["image"];?>" width="500" height = "600" align="left" border="1" /><?php echo "</td>" ;


echo "</tr>";
}
echo "</table>";

?>