nicoscodes

I have spent the last 3 weeks practically going insane. I have pretty much given myself anuerisms and had countless sleepless nights. 3 clients websites have been down and not functional because of this carriage return. You are a fucking god and I want to thank you so much.

Running linux, PHP version 5.2.17 error is line 1 where there is no PHP code.

The konnect.php file contains database connection (not using PDO): <?php $conn = mysql_connect('localhost', 'user', 'pass') or trigger_error("SQL", E_USER_ERROR); $db = mysql_select_db('data',$conn) or trigger_error("SQL", E_USER_ERROR); mysql_set_charset('utf8',$conn); ?> I have been troube shooting but cannot find where this error is coming from, would it be the host? the host supports PHP5 and I running locally on MAMP with no issues. I appreciate your help and thanks, what is my next course of action is the error log is giving me: Call to undefined function phpinclude()

Still coming up blank, nothing showing. In my php error log I am getting:

Locally It's working fine. Is there any error in the above code? Is the version of PHP on the server not supproting this? My text editor is saying i have zero synatax errors?

Hey guys, Nothing is showing up, just getting a blank white page, any suggestions? <?php include("include/konnect.php"); $sql=mysql_query("SELECT * FROM ask"); while($row=mysql_fetch_array($sql)) { $msg=$row['msg']; $mes_id=$row['mes_id']; $up=$row['up']; $down=$row['down']; echo " <div id='main'> <div class='box1'> <div class='up'><a href='' class='vote' id='".$mes_id."' title='Up' name='up'>".$up."</a></div> <div class='down'><a href='' class='vote' id='".$mes_id."' title='Down' name='down'>".$down."</a></div> </div> <div class='box2' > ".$msg." <br><br><div class='fb-comments' data-href='http://example.com/page.php?id=".$mes_id."' data-num-posts='2'></div><br><br> "; } ?>

I just didn't think it would be required as it is only the connection, but here is line 1 <?php include("include/conn.php"); ?>

Would this require me to change both: if(mysql_num_rows($r)>0): while($row = mysql_fetch_assoc($r)): As I mentioned I am a begginer, how would i properly execute this fix?

No luck there, still getting the PHP Parse error: syntax error, unexpected T_ENDIF error.

Hey guys, have a bit of a strange situation going on here. Locally (through mamp) the website loads fine (perfectly actually) and I find zero errors, however going live I face the infamous T_ENDIF error according to my error log. I had the code working remotely however made some changes to only the HTML, uploaded and like as if it was black magic I was faced with the error. I proceeded to trouble shoot and I had the document which was orginally working before I edited the HTML and uploaded that and it worked perfectly, I then took the working document and in my editor hit the space bar, again black magic the working document then gave the same error, I hit cmd+z to undo the spacebar, re-uploaded and still had zero luck. Is it just me or am I going insane? Here is my code: <?php if($post = $_GET["id"]) { echo "<div class='engage-search-result'>Search Result:</div>"; $q = "SELECT * FROM questions WHERE id = '$post'"; $r = mysql_query($q); if(mysql_num_rows($r)>0): while($row = mysql_fetch_assoc($r)): $net_vote = $row['votes_up'] - $row['votes_down']; ?> <div class='entry'> <div class='q_container'> <div class='left'> <a href='javascript:;' class='vote_up' id='<?php echo $row['id']; ?>'>Up</a> <span class='votes_count' id='votes_count<?php echo $row['id']; ?>'> <?php echo $net_vote.""; ?> </span> <a href='javascript:;' class='vote_down' id='<?php echo $row['id']; ?>'>Down</a> </div><!--// left--> <div class='right'> <span class='link'> <?php echo "<a href='engage.php?id=".$row['id']."'>".$row['question']."</a>"; ?><br><?php echo $row['categorey']; ?> <br><br> <?php echo "<div class='fb-comments' data-href='http://sitehere.com' data-num-posts='2'></div>"; ?> </span><!--// link (span)--> </div><!--// right--> </div><!--// q_container--> </div><!--// entry--> <?php endwhile; endif; ?> <?php } else { $q = "SELECT * FROM questions WHERE verified = 'y'"; $r = mysql_query($q); if(mysql_num_rows($r)>0): while($row = mysql_fetch_assoc($r)): $net_vote = $row['votes_up'] - $row['votes_down']; ?> <div class='entry'> <div class="q_container"> <div class='left'> <a href='javascript:;' class='vote_up' id='<?php echo $row['id']; ?>'>Up</a> <span class='votes_count' id='votes_count<?php echo $row['id']; ?>'> <?php echo $net_vote.""; ?> </span> <a href='javascript:;' class='vote_down' id='<?php echo $row['id']; ?>'>Down</a> </div><!--// left--> <div class='right'> <span class='link'> <?php echo "<a href='engage.php?id=".$row['id']."'>".$row['question']."</a>"; ?><br>#<?php echo $row['categorey']; ?> </a> <br><br> <?php echo "<div class='fb-comments' data-href='http://www.sitehere.com/engage.php?id=".$row['id']."' data-num-posts='1'></div>"; ?> </span><!--// link (span)--> </div><!--// right--> </div><!--// q_container--> </div><!--// entry--> <?php endwhile; endif; } ?> I call my DB connection at the top of the browser using include, the error log shows the error on line 1 where my DB connection is held. I am only a begginer with PHP and I am aware I am not using PDO. Any help would be greatly appreciated.

Hey guys! First time post here and I am only a begginer in programming. Anyway I have a few questions as I am stuck and have been for quite a while. I know this is a long post but it will cover the whole entire process of what I am doing at the moment. I really appreciate the time anyone can give me and will be happy to paypal someone over some $ for any help they can give me. Firstly, I am working with a bit of javascript and PHP. I am using a javascript method to update content from my table data in mysql without reloading the page. It works very well but I want to simplify the way i do things with the javascript so I am not left with repetative lines of code. Here is my javascript: $(document).ready(function() { //Edit link action (1) $('.edit_link').click(function(){$('.text_wrapper').hide(); var data=$('.text_wrapper').html(); $('.edit').show();$('.editbox').html(data);$('.editbox').focus();}); //Edit link action (2) $('.edit_link2').click(function(){$('.text_wrapper2').hide(); var data=$('.text_wrapper2').html();$('.edit2').show(); $('.editbox2').html(data);$('.editbox2').focus();}); //Mouseup textarea false (1) $(".editbox").mouseup(function(){return false}); //Mouseup textarea false (2) $(".editbox2").mouseup(function(){return false}); //Textarea content editing (1) $(".editbox").change(function(){$('.edit').hide();var boxval = $(".editbox").val(); var dataString = 'data='+ boxval;$.ajax({type: "POST",url: "update.php",data: dataString,cache: false,success: function(html){$('.text_wrapper').html(boxval);$('.text_wrapper').show();}});}); //Textarea content editing (2) $(".editbox2").change(function(){$('.edit2').hide(); var boxval = $(".editbox2").val();var dataString = 'data2='+ boxval;$.ajax({type: "POST",url: "update.php",data: dataString,cache: false,success: function(html){$('.text_wrapper2').html(boxval);$('.text_wrapper2').show();}});}); //Textarea without editing (1) $(document).mouseup(function(){$('.edit').hide();$('.text_wrapper').show();}); //Textarea without editing (2) $(document).mouseup(function(){$('.edit2').hide();$('.text_wrapper2').show();}); }); As you can see I am having to repeat the functions and all I do is change the name. Instead of repeating the script like I am over and over again to recognise different textareas is there a way I can array it or something like this so I don't have endless lines of the same code over and over again? I have allot more then just 2 textareas but of course shortened it for this post. Here is how I UPDATE the data in MySQL. I am looking into moving this over to PDO as I have be learning that PDO is the more safe and finctional option. My question here would be is there a simple way to UPDATE the rows instead of the way I doing this by repeating this process over and over again? I know I can use the: if (isset()); but I am troubled to work out how I would define the "id" of the data I am changing? <?php include("connection.php"); if($_POST['data']) { $data=$_POST['data']; $data = mysql_escape_String($data); $sql = "update slider set content='$data' where id='1'"; mysql_query( $sql); } if($_POST['data2']) { $data2=$_POST['data2']; $data2 = mysql_escape_String($data2); $sql = "update slider set content='$data2' where id='2'"; mysql_query( $sql); } ?> The HTML is quite simple. The form is wrapped in a div and the "edit" link is defined by class which again I repeat by just copy and past, the select is done via "id" which I need to define in the UPDATE section: <a href="#" class="edit_link" title="Edit">Edit</a> <? $sql=mysql_query("select content from slider where id='1'"); $row=mysql_fetch_array($sql); $profile=$row['content']; ?> <div class="text_wrapper" style=""><?php echo $profile; ?></div> <div class="edit" style="display:none"> <textarea class="editbox" cols="23" rows="3" name="profile_box"></textarea> </div> <a href="#" class="edit_link2" title="Edit">Edit</a> <? $sql=mysql_query("select content from slider where id='2'"); $row=mysql_fetch_array($sql); $profile=$row['content']; ?> <div class="text_wrapper2" style=""><?php echo $profile; ?></div> <div class="edit2" style="display:none"> <textarea class="editbox2" cols="23" rows="3" name="profile_box"></textarea> </div> I hate asking for help but I really need some guidence here as myself and Javascript are not good friends and myself and PHP are just starting a relationship, if you know what I mean. Any examples of how to achieve this? I do beleive if anyone could put me in the right direction it would be a great script to share around as it is very functional. I apologize for such a large post, however I really am stuck and have gone this far. I have researched google but find i just keep getting stuck. Idealy I just want to simplify the whole script, make it more functional and save myself the repetative task of going over the same thing again and again.