guybrown
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Posts posted by guybrown
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you can turn notices off, but you shouldn't, especially when learning php as you will also miss things like typo's and using wrong variable names. you will end up wasting hours of your time trying to find simple mistakes in your code if you hide any of the types of errors.
the correct coding for a variable that might not exist is to test if it isset() before using the value. using the short form of an if(){}else{} statement the code would be -
$var = isset($_GET["test"]) ? $_GET["test"] : '';
Thanks Mac_gyver! I'll try this.
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Hi all
I am doing a video tutorial on GET but I get a 'notice' that the tutor doesn't:
Notice: Undefined index: test in C:\xampp\htdocs\database\vartest2.php on line 2
Can I switch notifications like this off?
Here is the php code:
<?php$var = $_GET["test"];$len = strlen($var);if ($len > 0){echo $len;}else{echo "error: no input";}?><form action="vartest2.php" method="GET"><input type="text" name="test"><input type="submit" value="Submit"></form>This is what the tutor and I are entering into our browsers:
http://localhost/database/vartest2.php
(If I put ?test=anything at the end of the above, I don't get the notification but can't you just not specify ?test=... at the end?)
Displayed in my browser:
Notice: Undefined index: test in C:\xampp\htdocs\database\vartest2.php on line 2
error: no inputDisplayed on the tutor's browser:
error: no input
I'm using Google Chrome Version 27.0.1453.94 m
Any help appreciated.
Regards,
Guy Brown
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Hi Motion125. I am also new to this forum. I am learning html, css, php and mysql at the moment and know very little but I'm enjoying it. I joined this forum tonight because I needed some help and within 10 minutes I received some help so I'm impressed already. Hopefully I will be able to provide support to people one day when I'm more experienced. Good luck! Regards, Guy.
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Add semicolon( on lines
echo $query
echo $result
echo $views
Much appreciated pbs! Thank you very much. The echoes that were there to help me identify any issues were causing the issues. Cheers, Guy.
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Hi all
I'm new to programming and this forum and know very little about php. Any help would be greatly appreciated and I look forward to contributing and supporting others as my knowledge increases.
I am trying to get a 'counter' php file working on my localhost. When I run the php file in chrome I get the following error:
Parse error: syntax error, unexpected '$result' (T_VARIABLE), expecting ',' or ';' in C:\xampp\htdocs\database\counter.php on line 8
My php file contains the following:
<?phprequire($_SERVER["DOCUMENT_ROOT"]."/database/config/db_config.php");$connection = @mysql_connect($db_host,$db_user, $db_password) or die("error connecting");mysql_select_db($db_name, $connection);$query = "SELECT * FROM counter";echo $query$result = mysql_query($query, $connection) or die(mysql_error());echo $result$views = mysql_result($result, 0, "num_views");echo $views$views++;$query = "UPDATE counter SET num_views = $views";mysql_query($query, $connection) or die(mysql_error());echo "This page has been viewed ".$views." times.";?>I created the counter table in phpmyadmin and it has the following details:
# Name Type Collation Attributes Null Default Extra Action 1 num_views int(5) UNSIGNED No 0 Change Drop Browse distinct valuesAny help appreciated.
Regards,
Guy Brown
Notice: Undefined index: test
in PHP Coding Help
Posted
Works great. Now I can spend the evening understanding $var = isset($_GET["test"]) ? $_GET["test"] : '';
Much appreciated!