ThePHPNewbie
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displayLikes does not display anything. You might need to describe what you are actually doing.
function displayLikes($id) {$query = mysql_query("SELECT full_name FROM sociallike WHERE postid = '$id'") or die(mysql_error());while( $result = mysql_fetch_assoc($query) ) {echo $result['full_name']."likes";}}Theres the corrected code.Apologies again. -
displayLikes does not display anything. You might need to describe what you are actually doing.
Aaaa sorry! I was trying a couple of other things! I'll just undo a couple of things and upload.
Sorry for wasting your time!
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Hi There,
I have got this code:
function displayPosts() {$query = mysql_query("SELECT * FROM social ORDER BY id DESC") or die(mysql_error());while( $result = mysql_fetch_assoc($query) ) {echo '<div id="socialnewsfeeditem"><p id="newsfeeditemperson">'.$result["fullname"].'</p><p id="newsfeeditemcontent">'.$result["content"].'</p><p><center><a href="social.php?id='.$result["id"].'&do=like">Like!</a></center></p><div id="likes"><p>'.self::displayLikes($result["id"]).'</p></div></div>';}}function displayLikes($id) {$query = mysql_query("SELECT * FROM sociallike WHERE postid = '$id'") or die(mysql_error());}function like($id, $username) {$query2 = "INSERT INTO sociallike VALUES('$id', '$username')";mysql_query($query2);}But when I try to displayLikes the all come up all over the place on the page and I have no clue why it is doing this.I will upload the whole (functions.php) functions and the (social.php) php file on here.Many Thanks for Your Help
Help! My code isn't working for no reason!
in PHP Coding Help
Posted
Hi There,
I have got this code:
functions.php
social.php