pritithangjam

wanted to like your posts or thank you for your effort but i'm new here and i have no quota to do so

interesting turn of events. I got it fixed! Got help from another forum. It was to do with the database being case sensitive. I changed it to "Name" from "name" and it magically appeared thank you guys for all the help

i get this error when i do that: Notice: Undefined index: uc in /Applications/XAMPP/xamppfiles/htdocs/member1/rdvmembers-index.php on line 37 Notice: Undefined index: name in /Applications/XAMPP/xamppfiles/htdocs/member1/rdvmembers-index.php on line 38 here's the modified code: <?php session_start(); $dbhost = "localhost"; $dbname = "member1"; $dbuser = "root"; $dbpass = ""; mysql_connect($dbhost, $dbuser, $dbpass) or die("MySQL Error: " . mysql_error()); mysql_select_db($dbname) or die("MySQL Error: " . mysql_error()); ?> <?php if(!empty($_SESSION['LoggedIn']) && !empty($_SESSION['uc'])) { ?> <h3>Welcome</h3> <p>your uc is <strong><?=$_SESSION['uc']?></strong></p> <p>your name is <strong><?=$_SESSION['name']?></strong></p> <a href="logout.php">logout</a> <?php } elseif(!empty($_POST['uc']) && !empty($_POST['mobile'])) { $uc = mysql_real_escape_string($_POST['uc']); $mobile = md5(mysql_real_escape_string($_POST['mobile'])); $checklogin = mysql_query("SELECT * FROM users WHERE uc = '".$uc."' AND mobile = '".$mobile."'"); if(mysql_num_rows($checklogin) == 1) { $row = mysql_fetch_array($checklogin); $_SESSION['uc'] = $row['uc']; $_SESSION['name'] = $row['name']; $_SESSION['LoggedIn'] = 1; echo "<h1>Success - redirecting</h1>"; echo "<meta http-equiv='refresh' content='5;rdvmembers-index.php' />"; } else { echo "<h1>Error</h1>"; } } else { ?> <h1>Members Login</h1> <form method="post" action="rdvmembers-index.php" name="loginform" id="loginform"> uc <input type="text" name="uc" id="uc" size="40" /> mobile <input type="text" name="mobile" id="mobile" size="40"/> <input class="button_text" type="submit" name="login" id="login" value="Login" /> </form> <?php } ?> </div> </body> </html>

yes, that forum was just doing nothing but wasting my time and theirs by coming back to square one time and again. Felt like they are not reading my post but just replying for the sake of it. I don't understand. Where do i place print_r($row);?

I did as you asked and got the following error and output: Error: Notice: Undefined variable: name in /Applications/XAMPP/xamppfiles/htdocs/member1/rdvmembers-index.php on line 38 Output: Welcome your uc is 999 your name is logout here's the modified code as per your suggestion: <?php session_start(); $dbhost = "localhost"; $dbname = "member1"; $dbuser = "root"; $dbpass = ""; mysql_connect($dbhost, $dbuser, $dbpass) or die("MySQL Error: " . mysql_error()); mysql_select_db($dbname) or die("MySQL Error: " . mysql_error()); ?> <?php if(!empty($_SESSION['LoggedIn']) && !empty($_SESSION['uc'])) { ?> <h3>Welcome</h3> <p>your uc is <strong><?=$_SESSION['uc']?></strong></p> <p>your name is <strong><?=$_SESSION['name']?></strong></p> <a href="logout.php">logout</a> <?php } elseif(!empty($_POST['uc']) && !empty($_POST['mobile'])) { $uc = mysql_real_escape_string($_POST['uc']); $mobile = md5(mysql_real_escape_string($_POST['mobile'])); $mobile = md5(mysql_real_escape_string($_POST['mobile'])); $checklogin = mysql_query("SELECT * FROM users WHERE uc = '".$uc."' AND mobile = '".$mobile."'"); if(mysql_num_rows($checklogin) == 1) { $row = mysql_fetch_array($checklogin); $_SESSION['uc'] = $uc; $_SESSION['name'] = $name; $_SESSION['LoggedIn'] = 1; echo "<h1>Success - redirecting</h1>"; echo "<meta http-equiv='refresh' content='5;rdvmembers-index.php' />"; } else { echo "<h1>Error</h1>"; } } else { ?> <h1>Members Login</h1> <form method="post" action="rdvmembers-index.php" name="loginform" id="loginform"> uc <input type="text" name="uc" id="uc" size="40" /> mobile <input type="text" name="mobile" id="mobile" size="40"/> <input class="button_text" type="submit" name="login" id="login" value="Login" /> </form> <?php } ?> </div> </body> </html>

i added your code, same error. i replaced the two lines 37 & 38 with your code, still the same error. Could you be more specific please? Thanks.

I'm trying to display the "name" of a user who has successfully logged in to my website. It is based a simple open source script. Here's the fully working unmodified code which displays the name, uc as needed: <?php session_start(); $dbhost = "localhost"; $dbname = "member1"; $dbuser = "root"; $dbpass = ""; mysql_connect($dbhost, $dbuser, $dbpass) or die("MySQL Error: " . mysql_error()); mysql_select_db($dbname) or die("MySQL Error: " . mysql_error()); ?> <?php if(!empty($_SESSION['LoggedIn']) && !empty($_SESSION['uc'])) { ?> <h3>Welcome</h3> <p>your uc is <strong><?=$_SESSION['uc']?></strong></p> <p>your name is <strong><?=$_SESSION['name']?></strong></p> <a href="logout.php">logout</a> <?php } elseif(!empty($_POST['uc']) && !empty($_POST['mobile'])) { $uc = mysql_real_escape_string($_POST['uc']); $name = mysql_real_escape_string($_POST['name']); $mobile = md5(mysql_real_escape_string($_POST['mobile'])); $checklogin = mysql_query("SELECT * FROM users WHERE uc = '".$uc."' AND name = '".$name."' AND mobile = '".$mobile."'"); if(mysql_num_rows($checklogin) == 1) { $row = mysql_fetch_array($checklogin); $_SESSION['uc'] = $uc; $_SESSION['name'] = $name; $_SESSION['LoggedIn'] = 1; echo "<h1>Success - redirecting</h1>"; echo "<meta http-equiv='refresh' content='2;rdvmembers-index.php' />"; } else { echo "<h1>Error</h1>"; } } else { ?> <h1>Members Login</h1> <form method="post" action="rdvmembers-index.php" name="loginform" id="loginform"> uc <input type="text" name="uc" id="uc" size="40" /> name <input type="text" name="name" id="name" size="40" /> mobile <input type="text" name="mobile" id="mobile" size="40"/> <input class="button_text" type="submit" name="login" id="login" value="Login" /> </form> <?php } ?> </div> </body> </html> Now, i want to remove the name field from the "Members Login" form so that it ask for only UC and Mobile. The name to be displayed must be taken from the database on successful login. I modified the form and made a few changes to the code but no matter what changes i do, it won't display the "name". Where am i going wrong? here's the modified code: <?php session_start(); $dbhost = "localhost"; $dbname = "member1"; $dbuser = "root"; $dbpass = ""; mysql_connect($dbhost, $dbuser, $dbpass) or die("MySQL Error: " . mysql_error()); mysql_select_db($dbname) or die("MySQL Error: " . mysql_error()); ?> <?php if(!empty($_SESSION['LoggedIn']) && !empty($_SESSION['uc'])) { ?> <h3>Welcome</h3> <p>your uc is <strong><?=$_SESSION['uc']?></strong></p> <p>your name is <strong><?=$_SESSION['name']?></strong></p> <a href="logout.php">logout</a> <?php } elseif(!empty($_POST['uc']) && !empty($_POST['mobile'])) { $uc = mysql_real_escape_string($_POST['uc']); $name = mysql_real_escape_string($_POST['name']); $mobile = md5(mysql_real_escape_string($_POST['mobile'])); $checklogin = mysql_query("SELECT * FROM users WHERE uc = '".$uc."' AND name = '".$name."' AND mobile = '".$mobile."'"); if(mysql_num_rows($checklogin) == 1) { $row = mysql_fetch_array($checklogin); $_SESSION['uc'] = $uc; $_SESSION['name'] = $name; $_SESSION['LoggedIn'] = 1; echo "<h1>Success - redirecting</h1>"; echo "<meta http-equiv='refresh' content='2;rdvmembers-index.php' />"; } else { echo "<h1>Error</h1>"; } } else { ?> <h1>Members Login</h1> <form method="post" action="rdvmembers-index.php" name="loginform" id="loginform"> uc <input type="text" name="uc" id="uc" size="40" /> mobile <input type="text" name="mobile" id="mobile" size="40"/> <input class="button_text" type="submit" name="login" id="login" value="Login" /> </form> <?php } ?> </div> </body> </html> ERROR: Notice: Undefined index: name in /Applications/XAMPP/xamppfiles/htdocs/member1/rdvmembers-index.php on line 28 If i remove line 28, the error goes to line 30 and so forth. Can anyone figure this out for me? It seems plain simple.