keloa

Thanks, I was searching but the reason why I've posted this topic is because I was looking for someone with some experience to tell me about what software he is comfortable with.

hahahahahaha you didn't get me.When you are hiring someone online with full time job it's much cheaper than hiring someone who want to get an office ...etc about the tool I just got a quick look and yes as you said , sadly its an interview tool.still searching for a good tall to work online

Hi I have a small company so I cant hire programmers with full time or part time. And I got this idea to start a team online, so is there any software that will make the team work easier. I found this software : http://codassium.com/ I didn't get time to take a good look into it but I think it is what I need. so if there is any software can make this work more easy I hope you tell me about it.espically if it's a free software.

Will, I need this (edit)and (delete) to be buttons and when I click on edit I'm going to be able to edit some data from the database.and if I clicked on delete it will delete this row.

Hi I'm working in a project and I just finished the pagination system (in every page 2 results) but my problem is that I want to add some options beside every result.For example I have to resut which are (john,katy)I want them to be like this : John (Edit) (Delete) Katy (Edit) (Delete) This is my code : <?php include("wasata/inc/config.php"); mysql_query('SET NAMES "UTF-8"'); if(!isset($_GET['page'])){ $page = 1; }else{ $page = (int) $_GET['page']; $records_at_page = 2; $q = mysql_query('SELECT * FROM serv'); $records_count = @mysql_num_rows($q); @mysql_free_result($q); $page_count = (int) ceil($records_count / $records_at_page); if(($page > $page_count) || ($page <= 0)){ mysql_close($con); die('No More Pages'); } $start = ($page - 1) * $records_at_page; $end = $records_at_page; if($records_at_page != 0){ $q = mysql_query("SELECT * FROM serv ORDER BY id ASC LIMIT $start,$end"); while($o = mysql_fetch_object($q)){ echo $o->title .'<br />'; } } echo '<br />'; for($i = 1; $i<= $page_count; $i++){ if($page == $i){ echo $page; }else{ echo '<a href="m.php?page=' .$i . '">' .$i . '</a>'; if($i != $page_count){ echo ' - '; } } } } mysql_close($con); ?> So can any one Help please.

Thank you guys I solved it.

It doesn't fit with my requirements.I think [ rand(); ] is the best choice in my case but my problem is with the loop !

Thanks, I'll check it

I need it random for some security and privacy reasons.

First, can you show us the full code so that will be able to help you.Another thing is a suggestion,which is why don't you give the visitor the ability to write his name instead of "visitor".

New_order.php <?php session_start(); include ("inc/config.php"); include ("inc/header.php"); if(!isset($_SESSION['user'])){ header("Location: login.php"); }else{ ?> <center> <form method="POST" action="check_order.php"> عنوان الطلب : <input type="text" name="title" /><br /> تفاصيل الطلب :<textarea name="describtion"></textarea><br /> رابط الطلب ان وجد : <input type="text" size="70" name="url" /><br /> <input type="submit" value="تقديم الطلب" /> </form> </center> <?php include("inc/footer.php"); } ?> ^ it works fine the second file is : check_order.php <?php session_start(); include ("inc/config.php"); include ("inc/header.php"); if(!isset($_SESSION['user'])){ header("Location: login.php"); }else{ $title = $_POST['title']; $describtion = $_POST['describtion']; $url = $_POST['url']; $username = $_SESSION['user']; $track_number = rand(10000, 99999); if(empty($title)or empty($describtion)){ echo "الرجاء ملأ جميع الحقول المطلوبة"; }else{ $sql="SELECT * FROM serv WHERE(track_number='".$track_number."')"; $result = mysql_query($sql); $asc = mysql_fetch_assoc($result); $asc['tracknumber']; while ($track_number == $asc['tracknumber']) { $track_number = rand(10000, 99999); } $sql = "INSERT INTO serv(username,title,describtion,track_number,url) VALUES('$username','$title','$describtion','$track_number','$url')"; $result = mysql_query($sql); if(isset($result)){ echo "done"."<br />"."Your tracking number is $track_number"; }else{ echo "check your code"; } }} ?> The result: Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\Program Files (x86)\EasyPHP-DevServer-13.1VC9\data\localweb\firstproject\check_order.php on line 20 done Your tracking number is 10175 The problems are : 1-The error on line 20 2-the data didn't enter the database

Thanks but actually I'm trying to find the code

Hi I'm working in a small project and I need to make a random number that doesn't repeat.The activation codes are stored in the database (mysql database) but the thing is that I want php to do the following: 1- create a random number (I used the function (rand) and it did exactly what I needed ). 2-check if the code is already stored in the database and if it's already there it should create another code (which is not stored in the database). Thanks