[creating a simple date counter]

nice thats working, i used it like so:
 

$adate = strtotime('2013-10-30');

$bdate = strtotime('2013-10-31');

$now = mktime(0,0,0);

 

echo '<pre>';

printf("%-15s\t%s\n", ' ', ' ');

while ($adate < $bdate) {

    printf("%-15s\t%6d\n", 'this be how many days passed:<span>', floor(($now-$adate)/86400), '<span>' );

    $adate = strtotime('+1 days', $adate);

}

echo '</pre>';

now not exactly sure how to get this  number to print to a variable - i tried this and didnot succeed:
$howmanydayspassed =  printf("%-15s\t%6d\n", floor(($now-$adate)/86400) );

Really appreciate your help there you are awesome!

[creating a simple date counter]

hmm my php info says im runnning 

Version 5.2.17

, yet Im getting this error:
Fatal error: Call to undefined method DateTime::getTimestamp() 

[creating a simple date counter]

I tried this and got the following error: Fatal error: Class 'DatePeriod' not found

 

I guess maybe this is from a newer version of php i'm working with?

What is the purpose of $bdate? I'm unclear on that.

 

Thanks so much for your help its much appreciated!

[creating a simple date counter]

hi there trying to create a very simple date counter script here.

I just cant recall how to do all this.

There is a span of days starting at oct 30th, 2013 and I want to get todays date and then determine how many days have passed.

Am I even on the right track here? Any help would be mmuch appreciated!

 

my feeble attempt is below:

 

<?php 

$elvenportal = mktime(0,0,0,10,30,2011);

$now = mktime(date("H"),date("i"),date("s"),date("n"),date("j"),date("Y"));

$theeday = date("d")-1;

$late = date("H");

if ($late < 7) {$now = mktime(0,0,0,date("n"),$theeday,date("Y"));};

if ($_POST["dayz"] != "" ){

if ($_POST["month"] != "" ){

if ($_POST["year"] != "" ){

$now = mktime(0,0,0,$_POST["month"],$_POST["dayz"],$_POST["year"]);

};};};

$offset = $now - $elvenportal;

print $offset;

?>