yasirmehmood123

Any one could help me, I just want to select the latest image while sharing for face book from my website.

can you please provide me the sample code for using the Open graph API ?

I have also tried the same as suggested that Values should be picked from database rather than Qrystring but it gives the same result. I want to get latest image while sharing through FB share button but I dont know how FB picks another image randomly.

Hi, I have a page whihc gets Daily motion URL from another page and also location of Image. I have Face book share button on this page and want to show my inage while trying to share on FB. unfortunatley face book picks something wrong , and I use Open Graph Debug library then temporarily this picture issue gets resolved but it re-occures again if another URL is selected for sharing purpose. Code written in header of my page: <meta property="og:title" content="Greate Web SIte"/> <meta property ="og:url" content="http://www.MySIte.com/ShowMovie.php"/> <meta property ="og:type" content="website"/> <meta property="og:image:width" content="200" /> <meta property="og:image:height" content="200" /> <?php $selectedImage=$_GET['selectedImg']; // this param is passed from qry string whihc is sent by a previos page, I want to change this param every time parent page sends a request of new image. $ImageAddress='http://www.mySIte.com/'.$selectedImage; //creating URL of image , if i paste this URL in browser , image is fetched successfully. echo '<meta property="og:image" content="'.$ImageAddress.'"/>'; ?> <meta property="og:site_name" content="my Heading"/> <meta property="og:description" content="Bla Bla bla."/> Following is the java script that I have pasted under body tag: <div id="fb-root"></div> <script>(function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) return; js = d.createElement(s); js.id = id; js.src = "//connect.facebook.net/en_US/sdk.js#xfbml=1&version=v2.0"; fjs.parentNode.insertBefore(js, fjs); }(document, 'script', 'facebook-jssdk'));</script> following is button for FB share: echo '<div class="fb-post" data-href="'.$pageURL.'" data-width="500"></div>'; // URL that is passed as qry stirng are passed here. kindly do let me know that how can I display the exact image on every attelp to share something.