[Unable to pass objects as arguments]

I am trying to create a page which displays user profile. I have created two classes one is dbconnect(which is database class) and the other is Profile class(which shows profile).

 

Now I am trying to pass object of dbconnect class as arguments for the constructor of profile class. I am getting error undefined variable database_profile

 

Here is my code of profile php

	class Profile{
		
		private $user_id;
		private $profile_array;
		private $database_profile;
		
		public function __construct($user,dbconnect $database_link){ 
			$this->user_id = $user;
			$this->database_profile = $database_link;
		}
		
		public function make_array(){
			$sql = "SELECT * FROM users WHERE id = '$this->user_id'";	
			$result = $database_profile->run_query($sql);
			$profile_array = mysqli_fetch_array($result, MYSQLI_ASSOC);	
			echo $profile_array['first_name'];
		}
		
		public function show_profileinfo(){

		}
		
		public function profilepic(){
			return $profile_array['avatar'];
		}
		
	}
	
	//Loads database
	$database_connect = new dbconnect("localhost","root","");
	$database_connect->select_database("selftest");
	
	//Loads Profile
	$profile = new Profile($_SESSION['userid'],$database_connect);
	$profile->make_array();

Here is my code of dbconnect class

	class dbconnect{
		
		public $database_selected;
		private $data_select;
		
		public function __Construct($host,$user,$pass){
			$this->database_selected = mysqli_connect($host,$user,$pass);
			
			if (!$this->database_selected)
				echo "Connection to database failed";
			else
				echo "Connection to database successful!"; 
		}
		
		public function select_database($database_name){
			$this->data_select = mysqli_select_db($this->database_selected, $database_name);
			if(!$this->data_select)
				echo "Connection to table failed";
			else
				echo "Connection to table successful!"; 	
		}
		
		public function close_connection(){
			$close = mysqli_close($this->database_selected);
			
			if ($close)
				echo "<p>Connection successfully closed</p>";
			else
				echo "<p>Failure in closing connection</p>";
		}
		
		//Returns aither true or false
		public function run_query($sql){ 
			return $query_success = mysqli_query($this->database_selected,$sql);
		}
	}