I have a code on `page1.php` where I have an array of checkbox populated with mysql data through a query. I can successfully submit the value of the checked checkbox to the `page2.php`. But I want to submit it according to the sequence the checkbox was checked by the user. I´ve tried some javascript, but i´m not familiar to it.
My intention is to show on `page2.php` what the user selected, on a specific order, from the `page1.php` form
Any help will be appreciated.
Thanks
Here is my clean code.
**page1.php**
<?php
$query = "SELECT * FROM imoveis";
$result = mysql_query($query,$conn);
?>
<form action="page2.php" method="post">
<input type="submit" value="Create" id="enviarButton"/></td>
<br><br>
<table border="1">
<?
$i = 0;
echo "<tr>";
while($imovel = mysql_fetch_array($result)){
$name = $imovel['empreendimento'];
$id = $imovel['id'];
?>
<td>
<?=$name;?><br>
<input type="checkbox" name="op_imovel[]" value="<?=$id;?>">
</td>
<?
$i++;
if(($i % 3) == 0){
echo "</tr><tr>";
}
}
mysql_close();
?>
</table>
</form>
**page2.php**
<?php
$checkbox = $_POST['op_imovel'];
if (is_array($checkbox) && count($checkbox) > 0){
$res = '';
$tot = count($checkbox) - 1;
for ($y = 0; $y <= $tot; $y++) {
$res .=$checkbox[$y];
if ($y < $tot)
$res .= ",";
}
}
$query = "SELECT * FROM emps WHERE id IN ($res)";
$result = mysql_query($query,$conn);
?>
<br>
<div align="center">
<table border="1">
<?
$i = 0;
echo "<tr>";
if (is_array($checkbox) && count($checkbox) > 0){
while($imovel = mysql_fetch_array($result)){
$name = ($imovel['emp']);
?>
<td>
<p>
<?= $name;?>
</p>
</td>
<?
$i++;
if(($i % 3) == 0){
echo "</tr><tr>";
}
}
}
?>
</div>
<? mysql_close(); ?>
