mstoehr
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Posts posted by mstoehr
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Thank you for your input. Got it working now!!
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That's a great bit of code Thanks. But i still have a problem. As the loop continues staff run out of vacation weeks therefore they need to be skipped and the next person can pick in the round. How do i skip a staff member that has run out of days to pick?
The vac_pick_order -> vac_c_counter starts at the amount of vacation the staff is given and every week they pick is deducted from that count. When its 0 they should be skipped and the next person can pick.
$qq = ($row_admin['current_pick_staff'] + $row_admin['current_round_number'] - 2) % ($row_admin['total_staff']) + 1; $sql = "SELECT * FROM vac_pick_order WHERE pick_year='$year' vac_c_counter>0 && pick_order='$qq'"; $result = mysqli_query($conn, $sql); while($row = mysqli_fetch_assoc($result)){ if($row['vac_c_counter'] > 0){ $current_pick_emp_num = $row['emp_num']; }ELSE{ GOTO NEXT STAFF?????? } } -
This is my DB structure
~~~~~Table ~~~~vac_admin
Id | pick_year | current_pick_staff
-------------------------------------------------------------
1 | 2020 | 1~~~~~Table ~~~~vac_pick_order
Id | pick_year | pick_order | vac_c_counter | emp_number
-------------------------------------------------------------------------------------------------------------
1 | 2020 | 1 | 3 | 11111111
2 | 2020 | 2 | 5 | 22222222
3 | 2020 | 3 | 3 | 33333333~~~~~Table ~~~~vac_picks~~~the final result of picks
Id | pick_year | date | emp_number
-----------------------------------------------------------------------------
1 | 2020 | 2020-05-15 | 11111111
2 | 2020 | 2020-02-20 | 22222222
3 | 2020 | 2020-12-25 | 33333333 -
Man i just can't wrap my head around this bit of code 😫😫 I have been trying all day still not the result i need.
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SORRY I made a BIG ERROR explaining what i need . In every round the order changes by 1 every time
~~~~~~First round of picking~~~~~~
STAFF 1 - PICK ORDER 1 - 3 weeks available
STAFF 2 - PICK ORDER 2 - 5 weeks available
STAFF 3 - PICK ORDER 3 - 3 weeks availableStaff 1 takes 2 Weeks
Staff 2 takes 1 Weeks
Staff 3 takes 3 Weeks~~~~~~Second round of picking~~~~~~
STAFF 2 - PICK ORDER 1 - 4 weeks available
STAFF 3 - PICK ORDER 2 - No weeks left
STAFF 1 - PICK ORDER 3 - 1 weeks availableStaff 2 takes 3 Weeks
Staff 3 Skipped
Staff 1 takes 1 Weeks~~~~~~Third round of picking~~~~~~
STAFF 3 - PICK ORDER 1 - No weeks left
STAFF 1 - PICK ORDER 2 - No weeks left
STAFF 2 - PICK ORDER 3 - 1 weeks availableStaff 3 Skipped
Staff 1 Skipped
Staff 1 takes 1 Weeks~~~~~~~~~~~~
All staff 0 weeks left endthanks in advance for any help
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I have 3 staff members that need to pick vacation in a certain order.
Each have X weeks vacation and can pick off a calendar their choice 1-3 weeks per round.
I'm trying to loop through the DB to find who is next to pick with weeks left~~~~~~First round of picking~~~~~~
STAFF 1 - PICK ORDER 1 - 3 weeks available
STAFF 2 - PICK ORDER 2 - 5 weeks available
STAFF 3 - PICK ORDER 3 - 3 weeks availableStaff 1 takes 2 Weeks
Staff 2 takes 1 Weeks
Staff 3 takes 3 Weeks~~~~~~Second round of picking~~~~~~
STAFF 1 - PICK ORDER 1 - 1 weeks available
STAFF 2 - PICK ORDER 2 - 4 weeks available
STAFF 3 - PICK ORDER 3 - No weeks leftStaff 1 takes 1 Weeks
Staff 2 takes 3 Weeks
Staff 3 Skipped~~~~~~Third round of picking~~~~~~
STAFF 1 - PICK ORDER 1 - No weeks left
STAFF 2 - PICK ORDER 2 - 1 weeks available
STAFF 3 - PICK ORDER 3 - No weeks leftStaff 1 Skipped
Staff 2 takes 1 Weeks
Staff 3 Skipped~~~~~~~~~~~~
All staff 0 weeks left end--calendar.php-- $year=2020; $sql = "SELECT * FROM vac_admin WHERE pick_year='$year'; $result = mysqli_query($conn, $sql); if (mysqli_num_rows($result) > 0) { $row_admin = mysqli_fetch_assoc($result); } $current_pick_staff = $row_admin['current_pick_staff']; $sql = "SELECT * FROM vac_pick_order WHERE pick_year='$year' && pick_order = '$current_pick_staff'"; $result = mysqli_query($conn, $sql); $row = mysqli_fetch_assoc($result); if($row['vac_c_counter'] < 0){ $emp_num = $row['emp_num']; }ELSE{ ?????????????????? goto next staff with weeks > 0 ?????Somthing like if ($current_pick_staff == 3){ $current_pick_staff = 1; }ELSE{ $current_pick_staff++; } ?????????????????? } ~<FORM>~~~~~~~~~~~~~~~~~~~~~ Staff with $emp_num can now pick ~~~~~~ $_POST -> $date = XXXX-XX-XX; $num_weeks = X; $emp_num; ~</FORM>~~~~~~~~~~~~~~~~~~~~~ --process.php-- $year = 2020; $date = $_POST['date']; $num_weeks = $_POST['num_weeks']; $emp_num = $_POST['emp_num']; $sql = "INSERT INTO vac_picks (pick_year,emp_num,date) VALUES ($year,$emp_num,$date)"; $sql = "UPDATE vac_pick_order SET vac_c_counter=vac_c_counter - $num_weeks WHERE emp_num='$emp_num'; $sql = "UPDATE vac_admin SET pick_order=pick_order +1 WHERE pick_year='$year' ; Then back to calendar.php until all weeks gone.
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WOW so simple
Thank you works great
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I'm trying to get dates out of the DB for an overtime system. The dates are for staff with the oldest seniority first to the newest staff last.
But when 2 or more people start on the same date. I need to randomly order them every time i make a query to the DBIn my database, there is a column called start_date.
I need to select all the dates in order of oldest date to newest date.
$sql = "SELECT * FROM staff ORDER BY start_date DESC";
That's easy BUT...
If there are 2 or more of the same start dates selected those dates in random orderOUTPUT Example:
1988-01-01 <-- oldest date
1988-02-02
1990-01-01
1990-05-05
2000-01-01 <-- these 3 in random order
2000-01-01 <-- these 3 in random order
2000-01-01 <-- these 3 in random order
2000-02-05
2005-12-12
2006-02-02 <-- these 5 in random order
2006-02-02 <-- these 5 in random order
2006-02-02 <-- these 5 in random order
2006-02-02 <-- these 5 in random order
2006-02-02 <-- these 5 in random order
2010-05-09
2019-01-14 <-- newest date
etc
Set order for Staff Picking Vacation
in PHP Coding Help
Posted
$row_admin['total_staff'] = 5; //set in loop above $current_pick_staff = 1; //changes on page load AAAAWWWW: $sql = "SELECT * FROM vac_pick_order WHERE pick_order ='$current_pick_staff'"; $result = mysqli_query($conn, $sql); while($row = mysqli_fetch_assoc($result)){ if($row77['vac_c_counter'] > 0){ //<---- this is where the GOTO is needed if this goto the next staff member $current_pick_emp_num = $row77['emp_num']; }ELSE{ if ($current_pick_staff == $row_admin['total_staff']){ $current_pick_staff = 1; }ELSE{ $current_pick_staff++; } $sqla = "UPDATE vac_admin SET current_pick_staff='$current_pick_staff'"; if (mysqli_query($conn, $sqla)) { //echo "Record updated successfully a"; } else { echo "Error updating record: a " . mysqli_error($conn); } GOTO AAAAWWWW; }I think the GOTO is causing problems with my web host.It works fine on a local xampp server but not after uploading to Godaddy. It seems to freeze the server. How can i loop back to the beginning changing "$current_pick_staff" up by one without GOTO.
$current_pick_staff loops around 1->5 then back to 1 (1 2 3 4 5 1 2 3 4 5 and so on)