[[SOLVED] Put a square picture in the address bar.]

http://en.wikipedia.org/wiki/Favicon

[Loop from array]

if ($cell == 3)

[[SOLVED] php search in database with prev next ...]

I think the reason is that $_REQUEST[category] is lost when you move to next page. Add that in query parameter list

[[SOLVED] time diff in loop region]

simple answer: you cannot (you don't have to) use (declare) it in loop sequence.

 

Just take it out of the while-loop

[Jump to a paragraph on a php-page]

There's no such things as "php-page". Only html pages parsed with php

 

But, I'm pretty sure this would work:

 

index.php#text1?lessonNr=1&chapterNr=1

[Generating random gibberish]

So many nifty solutions for this one, here's one

 

http://www.tutorialized.com/tutorial/PHP-Random-String-Generator/13903

 

*couch*google*couch*

[[SOLVED] If variable is empty - Ignore lines in PHP ???]

$q =$_POST['q'];
$r =$_POST['r'];

if(!empty($q)) {
echo "http://www.mysite.com/images/$q/1";
}

if(!empty($r)) {
echo "http://www.mysite.com/images/$r/1";
}

[Is this possible in one query?]

min-function might work for you

 

http://www.tizag.com/mysqlTutorial/mysqlmin.php

 

that URL has a good example for your case

[[SOLVED] Uploading files from multipart forms problem]

Hello

 

Server upload limit (and the place to change it) depends on server.

 

Nothing you can do in code

[php mysql update - echo not updated list]

1. That code doesn't (even try to) print anything.

2. There's one mysql_query() before the actual sql expression is created. (might lead to unexpected errors)

 

[Form Validation]

strlen is a sufficient way of checking the length.

 

To get rid of empty strings (like spaces or tabs), use trim

[Change table row color from 2nd row onwards?]

how about this:

...
for(var i=1; i < trs.length; i++)
...

 

[[SOLVED] Image Trouble]

maybe src='' would work better

[one not working.]

variable in a database?

 

you mean column name?

 

maybe you should check the return value of mysql_query to see if it really fails, or just seems to fail

 

and if it fails, check mysql_error()

[[SOLVED] DOM background color to a cell]

another reason I hate JavaScript, strange naming conventions

 

also found a link that may help you in the future exploration

 

http://www.comptechdoc.org/independent/web/cgi/javamanual/javastyle.html

[one not working.]

sure $wagebill is not 0 ?

 

btw. all those parenthesis in your calculations are meaningless, considering basic arithmetics

[[SOLVED] PHP Form Processor and Checkbox array help]

it echoes 'Array' because it is an array...

 

if you want to echo all the values in the array, use something like

 

foreach($value in $student_03) {

echo $value;

}

[Code not working?]

as warewolfe already said, $query2 doesn't even slightly resemble an SQL query

[[SOLVED] PHP Form Processor and Checkbox array help]

you can catch the array just like the other posted variables:

e.g

 

$student_03 = $_POST['student_03'];

 

$student_03 is an array holding all the checked values

[simple]

whole query is pretty much f*cked up, the amount of single quotes is hurting my eyes

 

I think you are looking something like this (I persume $drugfact is variable, what else could it possibly be)

 

"UPDATE players SET drugs = drugs + $drugfact*300, dpayout = $drugfact*300"

 

You don't need single quotes unless you are working with varchars and alike

 

[[SOLVED] DOM background color to a cell]

oh, sorry I missed that

 

you could try

 

.style.background-color

 

Not on expert on JavaScript, but something I would try

[Strange SQL behaviour.]

Using single quotes with variables inside double quotes will print the variable name (not the value)

 

you'll need to escape those single quotes (\)

[[SOLVED] DOM background color to a cell]

document.getElementById('link').border

could work

 

document.getElementById('link').style.border

should work

[[SOLVED] only adding one.]

Your statements (opening and closing curly brackets) are a bit messed up:

 

that code will never enter to checking for 'steakhouse' if the $step == 'add'

 

btw. using e.g. switch-case statement would be cleaner and you would better avoid errors like such

 

 

[Basic array using end and while]

pretty sure it should be end($numbers)....

 

no more drinks for you!