niza
-
Posts
9 -
Joined
-
Last visited
Never
Posts posted by niza
-
-
I am trying calculate a date that occurs in the future. The date is stored in my database in date(""Y-m-d") format. I am not sure if I can make calculations with this format, so my question is how can I transform a date from date() format to time() format?
-
Don't worry about it. I solved my problem. Thanks anyway.
-
I have a user registration area:
new_member.php - script that executes the registration
new_member.htm - contains the html registration form
template.htm - html template
If the user does not fill in all the required fields, new_member.htm is called in new_member.php, with the appropiate error message.
Now, I have problems including my template.htm file.
1.If I include it in the new_member.htm, whenever the user does not fill in the required fileds, the error message are displayed on top of the template.
2.If I include it in the new_member.php, the form is not displayed properly.
Any ideas?
By the way, the script for user registration I am using is this: [a href=\"http://www.phpfreaks.com/tutorials/40/0.php\" target=\"_blank\"]http://www.phpfreaks.com/tutorials/40/0.php[/a]
-
Never mind. The variables were not being passes. I used this to get the variables:
$adName = $_POST['adName'];
$adInfo = $_POST['adInfo'];
And now it works.
Is there any way I can get the variables through a loop or something rather then manually give each variable a value?
-
I found the problem and I've fixed it. Now it updates the database but with nothing. I have no values in the database, only empty fields.
-
[code]$connection = mysql_connect($host, $user,$password)
or die ("Couldn't connect to server.");
$db = mysql_select_db($database, $connection)
or die ("Couldn't select database.");
$sql = "UPDATE ad SET adName='$adName', adInfo='$adInfo', adPrice='$adPrice' WHERE adID='21'";
$result = mysql_query($sql) or die("Couldn't modify database.");
mysql_close($connection); [/code]
This is the error I get: Couldn't modify database. Anyone knows what is happening and why I cannot update the database?
I checked all tables in the database for spelling mistakes and the variables. But I found no mistakes.
-
Here's my code:
[code]echo "<table cellspacing='10' border='0' cellpadding='0' width='100%'>";
echo "<tr><td width='20'></td>
<td>Ad Name</td></tr>";
while ($row = mysql_fetch_array($result,MYSQL_ASSOC))
{
extract($row);
echo "<tr><td>[b]<input name='vAd' type='radio' value='$adID'>[/b]</td>
<td>{$row['adName']}</td></tr>";
}
echo "<tr><td colspan='2' width='10'>
<table cellspacing='10' border='0' cellpadding='0' width='100%'>
<tr><td>[b]<a href='edit_add.php?id=$adID'>[/b]Edit</a></td></tr></table>
</td></tr></table>"; [/code]
I would like to pass the value $adID from the radio buttons
[code]<input name='vAd' type='radio' value='$adID'>[/code]
to this link here:
[code]<a href='edit_add.php?id=$adID'>Edit</a>[/code]
But no matter what radio button I choose, when I click the Edit link, the ID doesn't change. Any sugestions? Thanks. -
Hi everybody.
I am building a webpage with cell phone and accessories ads. Basically when someone wants to sell his/her cell phone will post an ad on my webpage.
I want to create a list/menu with the 3 categories (phones, accessories, cards), and pass the 3 values to category.php page.
Here's the code for the list/menu so far which is contained in the choose.php file:
echo "<select name='category'>\n";
echo "<option name='category' value='phones'>Phones</option>\n";
echo "<option name='category' value='accessories'>Accessories</option>\n";
echo "<option name='category' value='cards'>Cards</option>\n";
echo "</select>";
The query for the category.php page looks like this:
$query = "SELECT * FROM ad WHERE (and I want the value passed from the list/menu in here)"
I would also like to mention that the list/menu should have a onChange auction (I do not want a submit button) and it should take you to category.php page(this is also the page where the values should be passed to).
Thank you in advance.
Trying to setup a cron job
in PHP Coding Help
Posted
[!--quoteo--][div class=\'quotetop\']QUOTE[/div][div class=\'quotemain\'][!--quotec--]Type crontab -e
Ok now type 'i' and input something similar to: 30 * * * * /home/virtual/site/fst/var/www/html/cron.php.
Now push Escape then type :wq (it tells it to write the changes and then quit). It should say 'installing new crontab'. [/quote]
I did all of this,the message"installing new crontab" showed up but for some reason it does not work. Anyone has any ideas? Do I need to put a code in my script cron.php?
Thanks