Sware
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Posts posted by Sware
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Anyone?
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I don't think it works, it doesn't display anything.. How do I fix it?
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"$rssticker->recent-post->subject" doesn't return anything that can be plugged into a string.
I don't think I understand?
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I changed to this..
<?php echo "var pausecontent=new Array();"; echo "var rsstxt=" . $rssticker->recent-post->subject . ";"; echo "pausecontent[0]='rsstxt';"; echo "pausecontent[1]='<a href='#'>New Divisions Launched</a> - <i>7 Hours Ago</i>';"; echo "pausecontent[2]='<a href='#'>Welcome New Leaders</a> - <i>20 Hours Ago</i>';"; ?>
Now i'm getting "Parse error: syntax error, unexpected T_OBJECT_OPERATOR, expecting ',' or ';'"
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Bascially I have a Javascript script that has to have PHP elements in it. When I try to echo it all it doesn't work, and when I put PHP in the variable it still doesnt work.. Any luck?
This is what I currently have..
<?php echo "var pausecontent=new Array()"; echo "pausecontent[0]='$rssticker->recent-post->subject'"; echo "pausecontent[1]='<a href='#'>New Divisions Launched</a> - <i>7 Hours Ago</i>'"; echo "pausecontent[2]='<a href='#'>Welcome New Leaders</a> - <i>20 Hours Ago</i>'"; ?>
I tried it this way also.
pausecontent[0]='<?php $rssticker->recent-post->subject ?>';
No worky. Any suggestions?
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I need help I don't know if it's quite possible in PHP but I need it when an image is clicked it changes into a new image.
So the peusdo way is like
Image Click (Default: img1.png)
Image Click --> Change to img2.png
Image Click --> Change to img3.png
Image Click --> Change to img4.png
Then it raps around to Img1.png again.
Anyone know a good way about doing this?
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Paying 5$ per request and 10$ overall if someone can help me or do themselves (I'm not THAT great with PHP coding).
Basically take this PHP script
http://www.hotscripts.com/Detailed/70852.html
and having an option to format it as HTML when sent out as email. If someone can do that I'll pay $5.
also another $5 for whoever can make it so you can text box to put in multi emails address in it for like a mailing list of some sort. Not sure if its possible.
I can only pay via paypal.
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[code]<?PHP //MYSQL CONNECTION
$dbh=mysql_connect ("localhost", "XXXX", "XXXXXX") or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db ("sware_phpb2");
$query = "SELECT phpbb_users.username, phpbb_posts_text.post_subject, phpbb_posts_text.post_text, phpbb_posts.post_id, phpbb_posts.topic_id, phpbb_posts.forum_id FROM phpbb_users JOIN phpbb_posts ON phpbb_posts.poster_id = phpbb_users.user_id JOIN phpbb_posts_text ON phpbb_posts.post_id = phpbb_posts_text.post_id ORDER BY post_id DESC";
$result = mysql_query($query) or die(mysql_error());
// Contents
while($row = mysql_fetch_array($result)){
echo "<br>";
echo "<table border="0" cellpadding="0" cellspacing="2" width="510" class="pageoutline">";
echo "<tr>";
echo "<td width="504" height="19" valign="top" bgcolor="#A3C159"><div align="center" class="navtitle">";
echo "<div align="center">". $row['post_subject'] ."</div>";
echo "</div></td>";
echo "</tr>";
echo "<tr>";
echo "<td height="45" valign="top">"";
echo "Posted By:". $row['username'] .".";
echo "<p align="center">". $row['post_text'] .";
echo "<br>";
echo "</tr>";
echo "</table>";
}
?>[/code]
It says [code]Parse error: syntax error, unexpected T_LNUMBER, expecting ',' or ';' in /home/sware/public_html/test.php on line 13[/code]
Line 13 is [code] echo "<table border="0" cellpadding="0" cellspacing="2" width="510" class="pageoutline">";[/code] -
How do I add another join onto that
[code]SELECT phpbb_posts.poster_id, phpbb_users.username FROM phpbb_posts JOIN phpbb_users ON phpbb_posts.poster_id = phpbb_users.poster_id (+ ANOTHER JOIN)[/code]
or can you not do that? -
$query = "SELECT phpbb_posts.poster_id, phpbb_users.username FROM phpbb_posts, phpbb_users WHERE phpbb_posts.poster_id = phpbb_users.poster_id";
something like that? yes. -
Bump - Looked at once, not cool.
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I was doing fine and all of a sudden..
Bam!
Not unique table/alias: 'phpbb_posts'
I'm new to MySQL and trying to create a portal with phpBB.
$query = "SELECT phpbb_posts.poster_id, phpbb_users.username ".
"FROM phpbb_posts, phpbb_users".
"WHERE phpbb_posts.poster_id = phpbb_users.poster_id";
$result = mysql_query($query) or die(mysql_error());
// Print out the contents of each row into a table
while($row = mysql_fetch_array($result)){
echo $row['poster_id'];
echo $row['username'];
echo "<br />";
}
Just a little test but it shows that error, ANY help will be thanked for.
Javascript working with PHP
in PHP Coding Help
Posted
Is there a way to make that PHP rss feed into a Javascript Variable then?