DevinC

I am not sure why you recommended basename() as it is not what I was looking for. Anyway I have solved my own problem (without using regex) by replacing the line: $val = ltrim($val, $path); // strip path with $val = str_replace($path, "", $val); // strip path Thanks.

Hello, I am new to the regex and I'm hoping someone can assist me here on this: Objective: create a list of files using the glob() function and use regex to strip the path, leaving only the filename. i.e. Array ( [0] => ./dump/INCOMPLETE (do not move)/PERMANENT/123549.dmp [1] => ./dump/INCOMPLETE (do not move)/PERMANENT/139672.dmp [2] => ./dump/INCOMPLETE (do not move)/PERMANENT/dummy.dmp ) to Array ( [0] => 123549.dmp [1] => 139672.dmp [2] => dummy.dmp ) // File list generator without path // Usage: string argument must terminate with a trailing forwardslash function generateFilelistWithoutPath($path) { $pattern = $path . "*.dmp"; $filelist = glob($pattern); // generate list of file // print_r($filelist); if (!empty($filelist)) { //reconstruct array without path while (list($key, $val) = each($filelist)) { $val = ltrim($val, $path); // strip path if (!isset($filelistWithoutPath)) { $filelistWithoutPath = array($key => $val); // initialize } else { $filelistWithoutPath = array_merge($filelistWithoutPath, array($key => $val)); // merge to existing } } if (!isset($counter)) {$counter = 0;} // initialize for ($counter; $counter < count($filelistWithoutPath); ++$counter) { $file = "$filelist[$counter]"; $fileWithoutPath = "$filelistWithoutPath[$counter]"; } } return $filelistWithoutPath; } I realize that the Trim() function require $path in regex format but glob() require actual path so am I correct in thinking that I need to pass on two separate argument instead of 2-in-1? Thanks.