snake310
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Posts posted by snake310
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SO i`ll try to make this as clear as i can.
I would like ti have a simple textbox like :
<input name="serial" type="text" id="serial" />
My question is is it possible when i go to the page this texbox is already selected an i would not have click on it to write in it
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example:
$phrase="This is what i want";
I want to get out the words from the phrase one by one like:
$word1="This";
$word2="is";
and so on..
any idea any1?
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btw Problem solved thx for the help guys
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what i am listing there is a select list menu and now it goes like
model1
(blank)
(blank)
model2
(blank)
model3
and blank meant that it`s nothing there but it is selectible -
thx that is what i needed but there is still one thing it leaves blank fields... any ide what to do?
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i have a code:
$inter="SELECT model FROM $get2";
$id_rez=mysql_query($inter);
$row=mysql_num_rows($id_rez);
while($rand=mysql_fetch_row($id_rez))
for($i=0;$i<$row;$i++)
echo "<option>".$rand[$i]."</option>";
So this works fine , but i dont know how to evade to list every item just once , like if i have 3 of the same model i would like to show only 1
pls help i tried a lot of stuff it didnd`t work -
What is the problem in this source , is it even possible to do something like this :
$recordset="INSERT INTO `$table`";
$recordset .=" WHERE ";
$recordset .=" `$table`.serial = '$serial'";
$recordset .=" (OutTime, buyer) ";
$recordset .=" VALUES('$OutTime','$Buyer') ";
mysql_query($recordset);
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Thx problem solved ;D
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i get error : Fail
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Hi i have read tonns of tutorials but i cant figure out what could be the problem pls help me...
He wont write it to the database the wariables named $get1 and $producer works fine , at least as i echo them they show the right walue
<?php
mysql_pconnect("localhost","root")
or die("Unable to connect to SQL server");
mysql_select_db("$get1") or die ("No Conn");
if(!$producer)
$x=1;
else {
$sql = 'CREATE TABLE $producer ('.
'`model` varchar(60) NOT NULL default 0,'.
'`serial` varchar(60) NOT NULL default 0,'.
'`InTime` date NOT NULL default 0,'.
'`provider` varchar(60) NOT NULL default 0,'.
'`aviz` varchar(60) NOT NULL default 0,'.
'`OutTime` date NOT NULL default 0,'.
'`add1` varchar(60) NOT NULL default 0,'.
'`add2` varchar(60) NOT NULL default 0,'.
'`add3` varchar(60) NOT NULL default 0,'.
'`buyer` varchar(60) NOT NULL default 0,.
)';
$result = mysql_query($sql) or die ("Fail");}
?> -
Thx Thx Thx it worked ;D
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Hello
I have this at the satat of the page
$get1=$_GET['list'];
$get2=$_GET['list2'];
$get3=$_GET['list3'];
$serial=$_GET['serial'];
$InTime=$_GET['InTime'];
$provider=$_GET['provider'];
$validnumb=$_GET['validnumb'];
I think i don`t have to tell what it dose , what can i do to make list , list2, ... validnumb not an unidentified index??
and the error message :Notice: Undefined index: list in c:\program files\easyphp1-8\www\new prod.php on line 3
BTW i use these variables later in the page so when i reload the errormessages disapear and everything works fine.
Any1 has any idea?? ??? -
Hello
this listing works fine , the only thing is that i dont want to list the same named thing twice, any1 has any idea
if(!$get2)
echo "<option>step 3</option>";
$a=z;
$id_tab=mysql_list_fields($get1,$get2,$id);
$nr_col=mysql_num_fields($id_tab);
@mysql_select_db($get1);
$inter="SELECT model FROM $get2";
$id_rez=mysql_query($inter);
$row=mysql_num_rows($id_rez);
while($rand=mysql_fetch_row($id_rez))
for($i=0;$i<$row;$i++){
for($n=$i;$n=0;$n--)
if($rand[$i]=$rand[$n-1])
$a=$i;
if($i!==$a)
if($rand[$i]!=NULL)
echo "<option>".$rand[$i]."</option>"; }
if($_GET['list3']=NULL)
echo "<option selected>Please Select</option>";
else
echo "<option selected>".$get3."</option>";
?>
I sorry for makeing a new pst the same name but i accidentyly locked the other one -
Hello
this listing works fine , the only thing is that i dont want to list the same named thing twice, any1 has any idea
if(!$get2)
echo "<option>step 3</option>";
$a=z;
$id_tab=mysql_list_fields($get1,$get2,$id);
$nr_col=mysql_num_fields($id_tab);
@mysql_select_db($get1);
$inter="SELECT model FROM $get2";
$id_rez=mysql_query($inter);
$row=mysql_num_rows($id_rez);
while($rand=mysql_fetch_row($id_rez))
for($i=0;$i<$row;$i++){
for($n=$i;$n=0;$n--)
if($rand[$i]=$rand[$n-1])
$a=$i;
if($i!==$a)
if($rand[$i]!=NULL)
echo "<option>".$rand[$i]."</option>"; }
if($_GET['list3']=NULL)
echo "<option selected>Please Select</option>";
else
echo "<option selected>".$get3."</option>";
?>
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thx...
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Hello
cAn anyonr help me have a problem with writing to a mysql database with php
<?php
$query = "INSERT INTO asus ";
$query .= "(model, serial, ";
$query .= "InTime, provider) ";
$query .= " VALUES(a8n,123545,545464,45646)";
mysql_pconnect("localhost","root")
or die("Unable to connect to SQL server");
mysql_select_db("motherboards") or die("Unable to select database");
mysql_query($query) or die("Insert Failed!");
?>
Anyone hase any idea?
btw just the query has error the connection workes perfectly
[SOLVED] need help
in PHP Coding Help
Posted
Thanks for the help JavaScript helped