[call on variable variable via POST]

actually, that was the whole point, being able to acces them as they were afterwards...

anyway i got an error:

Warning: htmlspecialchars() expects parameter 1 to be string, array given in c:\phpdev\www\public\survey\vraag1.php on line 33

was i supposed to customize that piece of code?

edit:
aaah i get what you mean, the php script first generates the formname using the variable, then in the second page it generates a variable, using the formname that was compiled on the prevoious page,... well you'r right, thats not what i want, what i want is to have the complete syntax as it was before the compiling...

[call on variable variable via POST]

ok so when i do this script, i should be able to get all my POST varnames, without using $_POST['']?

i'll try this!!

[call on variable variable via POST]

i... dont think i quite understand everthing in that structure... what does the=> stand for?could you explain it a bit?

<?php

foreach( $_POST as $key => $value )
{
${$key} = htmlspecialchars($value);
}

?>

[call on variable variable via POST]

well what i want to do :
call on a variable wich was used in the previous page.I did this with POST.
so my ode would look like this:

<input name="awnser1">

-->then the code would be:

$awnser=$_POST['awnser1']

but the clue is that the thing i use POST on is also a variable:
so i get for instance:


<? $page_n=1; ?>
<input name="anwser<?echo"$page_n"?>">

so the server would compile the above as <input name="awnser1">
what i want to use in the next page now is the value "awnser$page_n", but i can't find a way to do this...

[call on variable variable via POST]

hello
what i want to exactly is this:
in my code, i have used POST to get a variable to the next page. but the variable itself is also a variable.

for instance:

[code]<? $pagenumber= "2" ?>
<input name="page<?echo="$number"; ?>"[/code]

so my question is, how do i call on this variable in the next page?
these are the ones that i have tried yet.

[code] $pagenumber=$_POST['page' . '$number']
$pagenumber=$_POST['page$pagenumber'] [/code]

none of these work actually, and i even dont know wether its possible, but it would be unlogical if it weren't, wouldn't it.

If you have a way of making this work, via POST or other, let me know! the main idea is to get the value of a variable to the next page, and the value of this variable is" $variable" (yeah i know its darn confusing ;D)

thanks
OranniS

[somethings wrong with the mysql_num_rows(]

hi
i was making a start page, where one must register a personal code, as in password, to proceed to the main site.

to check if the code has already been used by someone else, i used the mysql_num_rows() function, but somethings making it fail...

this is where i define a function wich is causing the whole jam. ive tried echoeing here and there, turns out the line with the error is the one with the
$count = mysql_num_rows($result) or die(mysql_error());...


[code]PHP Code:
<?php
    session_start();
    require_once('vars.php');
   
    //connectie maken met DB
            $db = mysql_connect("localhost", "dieetopmaat_be", "dieetDB") or die(mysql_error());
            mysql_select_db(dieetopmaat_be, $db) or die(mysql_error());
   
    function check_presence($table, $row, $value){
   
        $sql = "SELECT *    FROM $table
                            WHERE $row = '$value'";
        $result = mysql_query($sql) or die(mysql_error());

        $count = mysql_num_rows($result) or die(mysql_error());

    if($count >= 1)
        {
        return TRUE;
    }else
        {
        return FALSE;
    }[/code]


thanks to anyone who replies!
OranniS

ps: dont mind the language, its written in dutch