bidgeir
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returning an array from a function
in PHP Coding Help
Posted
I am trying to call a function inside a while loop which returns a array. The script seems to stop running when I call the function and I dont know why. Here is part of my code:
The bold code is where I call my function.
while ($row=mysql_fetch_array($result))
{
$types = $row['type'];
echo '<h3>' . $types . '</h3>';
[b]$ar = getProduct($types);[/b]
echo "bla";
foreach($ar as $value)
{
echo "<tr height='30'><td width='150'>" . $value . "</td><td width='50'> </td><td width='50'>
9 tommur</td><td width='50'><input type='checkbox' name='9inch'></td><td width='50'>12 tommur</td>
<td width='50'><input type='checkbox' name='12inch'></td><td width='50'>16 tommu</td>
<td width='50'><input type='checkbox' name='16inch'></td><td width='50'>Fjöldi</td><td width='50'><input type='text' name='qt'></td></tr>";
}
$counter++;
}
Here is the function:
function getProduct($type)
{
include 'db.php';
if (!($connection = @ mysql_pconnect($hostName,
$username,
$password)))
die("Could not connect to database");
if (!mysql_select_db($databaseName, $connection))
showerror();
$theType = $type;
$query = "SELECT name FROM products WHERE type='$theType'";
if (!($result = @ mysql_query($query1, $connection)))
showerror();
$row=mysql_fetch_array($result);
return ($row);
}
The script shows everything until I call the function. I added echo "bla"; to see if anything happend after the call, but it doesnt.
Hope someone can help,
Ásgeir